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3 years ago

A student uses a force of 46 Newtons to push her bike 57 meters. How much work has she done?

Chemistry

1 answer:

nordsb [41]3 years ago

4 0

Answer:

The displacement is 0.05 meters. The angle between the upward force and the upward displacement is 0 degrees. The work for 1 push-up is approximately. W = 10 N * 0.05 m * cos 0 degrees = 0.5 Joules. If the squirrel does a total of 5.0 Joules of work, then it must have done about 10 push-ups.

Explanation:

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which conversion factor do you use first to calculate the number of grams of fecl3 produced by the reaction of 30.3 g of fe with

Alexeev081 [22]

Answer:

Explanation:

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3 years ago

Approximately how many particles are in 2 moles?

schepotkina [342]

Answer:

$1.2\times10^2^4$ particles in 2 moles.

Explanation:

The number of particles that are contained in one mole, the international unit of amount of substance: by definition, exactly 6.022×10²³, and it is dimensionless. It is named after the scientist Amedeo Avogadro.

It is also known as Avogadro's constant.

∴ Number of particles in one mole = $6.022\times10^2^3$

∴ Number of particles in 2 mole = 2 times Number of particles in one mole

∴ Number of particles in 2 mole= $2\times6.022\times10^2^3=12.044\times10^2^3\approx1.2\times10^2^4$

Hence there are $1.2\times10^2^4$ particles in 2 moles.

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3 years ago

Read 2 more answers

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4 years ago

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I believe it’s D because they are the largest decimals

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3 years ago

Tetrachloromethane, CCl4 is produced from the substitution reaction between methane and chlorine gas. If the rate of formation o

Korolek [52]

The rate of disappearance of chlorine gas : 0.2 mol/dm³

<h3>Further explanation</h3>

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.

For reaction :

$\tt aA+bB\rightarrow cC+dD$

The rate reaction :

$\tt -\dfrac{1}{a}\dfrac{d[-A]}{dt}= -\dfrac{1}{b}\dfrac{d[-B]}{dt}=\dfrac{1}{c}\dfrac{d[C]}{dt}=\dfrac{1}{d}\dfrac{d[D]}{dt}$

Reaction for formation CCl₄ :

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From equation, rate of reaction = rate of formation CCl₄ = 0.05 mol/dm³

Rate of formation of CCl₄ = reaction rate x coefficient of CCCl₄

0.05 mol/dm³ = reaction rate x 1⇒reaction rate = 0.05 mol/dm³

The rate of disappearance of chlorine gas (Cl₂) :

Rate of disappearance of Cl₂ = reaction rate x coefficient of Cl₂

Rate of disappearance of Cl₂ = 0.05 x 4 = 0.2 mol/dm³

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3 years ago