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Digiron [165]
3 years ago
6

What is the mass of 6.02 × 10²³ hydrogen atoms​

Chemistry
1 answer:
Leviafan [203]3 years ago
5 0

Answer:

2

Explanation:

because you add this and that.

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If a solid piece of naphthalene is heated and remains at 80°C until it is completely melted, you know that 80ºC is the
Rom4ik [11]

Answer: Melting point of the naphthalene is 80^oC.

Explanation:

Melting point of a substance is temperature at which given solid changes its state from solid to liquid. It is also referred as freezing point of the substance.

Freezing point of substance is a temperature at which given substance changes its state from liquid to solid.

Here, the solid piece of naphthalene is heated and remains at 80°C until it is completely melted.

6 0
3 years ago
Read 2 more answers
Be sure to answer all parts. The standard enthalpy of formation and the standard entropy of gaseous benzene are 82.93 kJ/mol and
skelet666 [1.2K]

Answer : The values of \Delta H^o,\Delta S^o\text{ and }\Delta G^o are 33.89kJ,95.94J/K\text{ and }5.299kJ/mol respectively.

Explanation :

The given balanced chemical reaction is,

C_6H_6(l)\rightarrow C_6H_6(g)

First we have to calculate the enthalpy of reaction (\Delta H^o).

\Delta H^o=H_f_{product}-H_f_{reactant}

\Delta H^o=[n_{C_6H_6(g)}\times \Delta H_f^0_{(C_6H_6(g))}]-[n_{C_6H_6(l)}\times \Delta H_f^0_{(C_6H_6(l))}]

where,

\Delta H^o = enthalpy of reaction = ?

n = number of moles

\Delta H_f^0_{(C_6H_6(g))} = standard enthalpy of formation  of gaseous benzene = 82.93 kJ/mol

\Delta H_f^0_{(C_6H_6(l))} = standard enthalpy of formation  of liquid benzene = 49.04 kJ/mol

Now put all the given values in this expression, we get:

\Delta H^o=[1mole\times (82.93kJ/mol)]-[1mole\times (49.04J/mol)]

\Delta H^o=33.89kJ/mol=33890J/mol

Now we have to calculate the entropy of reaction (\Delta S^o).

\Delta S^o=S_f_{product}-S_f_{reactant}

\Delta S^o=[n_{C_6H_6(g)}\times \Delta S^0_{(C_6H_6(g))}]-[n_{C_6H_6(l)}\times \Delta S^0_{(C_6H_6(l))}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S^0_{(C_6H_6(g))} = standard entropy of formation  of gaseous benzene = 269.2 J/K.mol

\Delta S^0_{(C_6H_6(l))} = standard entropy of formation  of liquid benzene = 173.26 J/K.mol

Now put all the given values in this expression, we get:

\Delta S^o=[1mole\times (269.2J/K.mol)]-[1mole\times (173.26J/K.mol)]

\Delta S^o=95.94J/K.mol

Now we have to calculate the Gibbs free energy of reaction (\Delta G^o).

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

At room temperature, the temperature is 25^oC\text{ or }298K.

\Delta G^o=(33890J)-(298K\times 95.94J/K)

\Delta G^o=5299.88J/mol=5.299kJ/mol

Therefore, the values of \Delta H^o,\Delta S^o\text{ and }\Delta G^o are 33.89kJ,95.94J/K\text{ and }5.299kJ/mol respectively.

6 0
3 years ago
Read 2 more answers
Check all substances that are excreted in humans.<br> 1.carbon dioxide<br> 2.urine<br> 3.salvia
Tatiana [17]

carbon dioxide and urine

8 0
3 years ago
The cap-like ________ covers the head of the sperm and releases enzymes that will help the sperm penetrate the egg.
Licemer1 [7]

The cap-like acrosome covers the head of the sperm and releases enzymes that will help the sperm penetrate the egg.

<h3>What is acrosome?</h3>

The acrosome is a unique membrane organelle found over the anterior region of the sperm nucleus that has been largely preserved throughout evolution. This acidic vacuole includes a number of hydrolytic enzymes that, when produced, aid sperm penetration of the egg covers.

<h3>What is acrosome made of?</h3>

The acrosome is formed from the Golgi complex of the spermatid. The acrosome is made up of a protein matrix core and multiple hydrolytic and glycolytic enzymes that are essential for fertilization.

To know more about acrosome visit:

brainly.com/question/16245783

#SPJ4

7 0
2 years ago
Hydrogen chloride and oxygen react to form chlorine and water, like this:
jarptica [38.1K]

Answer:

The equilibrium constant Kp for this reaction is 0.0030

Explanation:

Step 1: Data given

Partial pressure at the equilibrium:

pHCl = 76.9 atm

pO2 = 66.3 atm

pCl2 = 40.7 atm

pH2O = 65.1 atm

Step 2: The balanced equation

4 HCl(g) + O2(g) → 2 Cl2(g) + 2 H2O(g)

Step 3: Calculate the equilibrium constant Kp

Kp = ((pH2O²)*(pCl2²)) /(pO2)*(pHCl^4))

Kp =  (65.1²*40.7²) / (66.3*(76.9^4))

Kp = 0.0030

The equilibrium constant Kp for this reaction is 0.0030

8 0
3 years ago
Read 2 more answers
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