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Arisa [49]
3 years ago
7

this is my third time asking this,,, HELPPPPPP PLZZZz i'll mark brainliest! Infrared (IR) and ultraviolet (UV) light. But above

29°C, the coating on the glass undergoes a chemical change, causing it to block IR light. What happens to the IR light?
Chemistry
1 answer:
mezya [45]3 years ago
5 0

Answer:it would not cause any effect because its blocking it. Basically u could say that what would happen is that no effect was happening cuz of the blocking.

Explanation:

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What is a warm front
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Answer:the Boundary of an advancing mass of warm air, in particular the leading edge of the warm sector of a low-pressure system.

Explanation:

3 0
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25 points!!! please Which types of elements areconsidered neutraland Where are these types of elements found on the periodic tab
posledela

Elements which composed of an equal amount of three components protons, neutrons and electrons are considered neutral elements. example of neutral elements are hydrogen, helium, lithium and beryllium...

7 0
2 years ago
Ca+Cl2-->CaCl2 Then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction.
kompoz [17]

Answer:

Oxidation half

Ca -----> Ca2+ +2elecyrons

Reduction half

Cl2 + 2electrons ------> 2Cl-

Explanation:

8 0
3 years ago
A farmer is analyzing cross sections of his land to determine where to build a well.
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Jahsjavana Shabbat a
7 0
3 years ago
If aqueous solutions of sodium chloride and mercury(I) nitrate are mixed, which insoluble precipitate is formed?
NeX [460]

Answer:

Hg2^2+(aq) + 2Cl^-(aq) —> Hg2Cl2(s)

Explanation:

The balanced equation for the reaction is given below:

2NaCl(aq) + Hg2(NO3)2(aq) —> 2NaNO3(aq) + Hg2Cl2(s)

Considering the states of each compound in the reaction, we can see that Hg2Cl2 is in solid form meaning it will precipitate out of the solution

In solution the following occurs:

NaCl —> Na+(aq) + Cl-(aq)

Hg2(NO3)2 —> Hg2^2+(aq) + 2NO3^-(aq)

Combining the two equation together, a balanced double displacement reaction occurs as shown below:

2Na+(aq) + 2Cl-(aq) + Hg2^2+(aq) + 2NO3^-(aq) —> 2Na+2NO3^-(aq) + Hg2^2+2Cl-(s)

From the above we can thus right the insoluble precipitate as

Hg2^2+(aq) + 2Cl^-(aq) —> Hg2Cl2(s)

7 0
3 years ago
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