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4 years ago

Tetrachloromethane,CC15,is classified as a

Chemistry

1 answer:

prohojiy [21]4 years ago

7 0

Correct Answer: compound because the atoms of the elements are combined in a fixed proportion.

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A 32 L samples of xenon gas at 10°C is expanded to 35 L. Calculate the final temperature.

morpeh [17]

Answer:

Final Temperature = 36.54 ⁰C

Explanation:

Lets suppose the gas is acting ideally, then according to Charle's Law, "<em>The volume of a fixed mass of gas at constant pressure is directly proportional to the absolute temperature</em>". Mathematically for initial and final states the relation is as follow,

V₁ / T₁ = V₂ / T₂

Data Given;

V₁ = 32 L

T₁ = 10 °C = 283.15 K ∴ K = °C + 273.15

V₂ = 35 L

T₂ = ??

Solving equation for T₂,

T₂ = V₂ × T₁ / V₁

Putting values,

T₂ = (35 L × 283.15 K) ÷ 32 L

T₂ = 309.69 K ∴ ( 36.54 °C )

Result:

As the volume is increased from 32 L to 35 L, therefore, the temperature must have increased from 10 °C to 36.54 °C.

3 0

4 years ago

How many grams of potassium chloride are required to make 250 ml of a 0.75 m kcl solution?

DedPeter [7]

Answer:

The solution would need 13.9 g of KCl

Explanation:

0.75 m, means molal concentration

0.75 moles in 1 kg of solvent.

Let's think as an aqueous solution.

250 mL = 250 g, cause water density (1g/mL)

1000 g have 0.75 moles of solute

250 g will have (0.75 . 250)/1000 = 0.1875 moles of KCl

Let's convert that moles in mass (mol . molar mass)

0.1875 m . 74.55 g/m = 13.9 g

7 0

3 years ago

Which formula is an empirical formula?

poizon [28]

<h2>Hello!</h2>

The answer is:

The empirical formula is the option B. $NH_{3}$

The empirical formula of a compound is the simplest formula that can be written. On the opposite, the molecular formula involves a variant of the same compound, but it can be also simplified to an empirical formula.

$MolecularFormula=n(EmpiricalFormula)$

We are looking for a formula that cannot be simplified by dividing the number of molecules/atoms that conforms the compound.

Let's discard option by option in order to find which formula is an empirical formula (cannot be simplified)

A. $N_{2}O_{4}$

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

$N_{2}O_{4}=2(NO_{2})$

B. $NH_{3}$

It's an empirical formula since it cannot be obtained by the multiplication of a whole number and the simplest formula. It's the simplest formula that we can find of the compound.

C. $C_{3}H_{6}$

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

$C_{3}H_{6}=3(CH_{2})$

D. $P_{4}O_{10}$

It's not an empirical formula, it's a molecular formula since it can be obtained by multiplying the empirical formula of the same compound.

$P_{4}O_{10}=2(P_{2}O_{5})$

Hence, the empirical formula is the option B. $NH_{3}$

Have a nice day!

6 0

3 years ago

Read 2 more answers

the decomposition of calcium carbonate to calcium oxide and carbon dioxide only takes place at very high temperatures, making th

USPshnik [31]

So calculate the H for the other two reactions a room temperature and combine the reactions to calculate the H of the decomposition of calcium carbonate using the Hess's Law

4 0

3 years ago

How many protons and neutrons are in the nucleus of isotope with mass of 68.926 amu?

Sidana [21]

There are 30 protons and 39 neutrons in the nucleus.

This must me the isotope of an element with an atomic mass close to 69 u.
The only candidates are Zn and Ga.
Zn has a zinc-69 isotope with mass 68.926 u.
Ga has a gallium -69 isotope with mass 68.925 u.
The isotope is probably $_{30} ^{69}Zn$ .
It has 30 protons and 39 neutrons.

4 0

3 years ago