Answer:
6Fe^2+(aq) -------> 6Fe^3+(aq) + 6e
Explanation:
The balanced oxidation half equation is;
6Fe^2+(aq) -------> 6Fe^3+(aq) + 6e
A redox reaction is actually an acronym for oxidation-reducation reaction. Since the both reactions are complementary, there can't be oxidation without reduction and there can't be reduction without oxidation.
The main characteristic of redox reactions is that electrons are transferred in the process. The number of electrons transferred is usually deduced from the balanced reaction equation. For this reaction, the balanced overall reaction equation is;
Cr2O7^2–(aq) + 6Fe^2+(aq) +14H^+(aq)→ 2Cr^3+(aq) + 6Fe^3+ (aq) + 7H2O(l)
It is clear from the equation above that six electrons were transferred. Thus six Fe^2+ ions lost one electron each in the oxidation half equation as shown in the balanced oxidation half equation above.
Answer:
That involve the complete transfer of an electron from one atom of an element to another
A match-head is flammable, but you have to get it up to its ignition temperature first.
A diamond is flammable, but its ignition temperature is astronomical and
totally out of sight.
Answer:
![\mathrm{Ca}^{2+} \text { and } \mathrm{Cl} \text { - ions are present in } 1: 2 \text { ratio in a solution of aqueous calcium chloride. }](https://tex.z-dn.net/?f=%5Cmathrm%7BCa%7D%5E%7B2%2B%7D%20%5Ctext%20%7B%20and%20%7D%20%5Cmathrm%7BCl%7D%20%5Ctext%20%7B%20-%20ions%20are%20present%20in%20%7D%201%3A%202%20%5Ctext%20%7B%20ratio%20in%20a%20solution%20of%20aqueous%20calcium%20chloride.%20%7D)
Explanation:
Here in Calcium Chloride ionic bond is present in between calcium and chlorine atoms. As we know according to Octet rule calcium have two excess atoms and for matching nearest noble gas electronic configuration. It donate two electrons to gain more stability and form
, while chlorine is deficient from one electron to meet nearest noble gas electronic configuration therefore two chlorine atoms accept excess electron from calcium individually and form two
ions.
![\text { Equation is as follows: } \mathrm{Ca}^{2+}+2 \mathrm{Cl}^{-} \rightarrow \mathrm{CaCl}_{2}](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Equation%20is%20as%20follows%3A%20%7D%20%5Cmathrm%7BCa%7D%5E%7B2%2B%7D%2B2%20%5Cmathrm%7BCl%7D%5E%7B-%7D%20%5Crightarrow%20%5Cmathrm%7BCaCl%7D_%7B2%7D)
Hence aqueous solution of calcium chloride breaks the ionic bond pairing in one
and two
ions: ![\mathrm{CaCl}_{2} \longrightarrow \mathrm{H}_{2} \mathrm{O} \quad \mathrm{Ca}^{2+}(\mathrm{ag})+2 \mathrm{Cl}(\mathrm{ag})](https://tex.z-dn.net/?f=%5Cmathrm%7BCaCl%7D_%7B2%7D%20%5Clongrightarrow%20%5Cmathrm%7BH%7D_%7B2%7D%20%5Cmathrm%7BO%7D%20%5Cquad%20%5Cmathrm%7BCa%7D%5E%7B2%2B%7D%28%5Cmathrm%7Bag%7D%29%2B2%20%5Cmathrm%7BCl%7D%28%5Cmathrm%7Bag%7D%29)
Carbonyl Compounds containing
alpha proton readily donates alpha acidic proton when treated with
strong Base. In given statement <span>
2-phenylacetaldehyde is converted into Enolate and Enolates acts as a nucleophile and attacks carbonyl group of
Benzaldehyde. The mechanism of given reaction is as follow, the movement of electrons is shown by
RED arrows,</span>