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3 years ago

Tetrachloromethane,CC15,is classified as a

Chemistry

1 answer:

prohojiy [21]3 years ago

7 0

Correct Answer: compound because the atoms of the elements are combined in a fixed proportion.

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Please help me with this homework

KengaRu [80]

Answer:

The answer is C density.

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2 years ago

When a toaster in use electrical energy is transformed into

jeka57 [31]

An electric toaster takes in electrical energy from the power outlet and converts it into heat, very efficiently. If you want your toast to cook quickly, you need a toaster that radiates as much heat as possible each second onto your bread.

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3 years ago

Read 2 more answers

If 35.00 mL of 3.00 M KOH reacted completely (according to our equation), what mass of aluminum has reacted?

Shalnov [3]

Answer:

Explanation:

25 Mass

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3 years ago

1. Write an unbalanced equation to represent each of the following equations. (Make sure to

notsponge [240]

The equation for each reaction is written according to the relevant as below.

<h3>Equations of chemical reactions</h3>

The reaction between iron and sulfur to form iron (II) sulfide is written as:

$Fe + S --- > FeS$

The reaction between hydrogen gas and oxygen gas to form water is written as:

$H_2 (g) + O_2 (g) --- > H_2O (l)$

The reaction of aluminum oxide to form aluminum and oxygen gas is written as:

$Al_2O_3 --- > Al + O_2$

Zinc and copper(II) sulfate react to form zinc(II) sulfate and copper as follows:

$Zn+CuSO_4--- > ZnSO_4+Cu$

Potassium hydroxide and hydrogen bromide react to form potassium bromide and water as follows:

$KOH + HBr --- > H_2O + KBr$

More on equations of chemical reactions can be found here: brainly.com/question/6976143

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2 years ago

A piston-cylinder device has two stops; a lower set and an upper set, that constrain the cylinder. When the piston is on the low

stich3 [128]

Answer:

2080kJ

Explanation:

m(U4 - U1) = Q4 - W4

If P is less than 300kpa, then V = 0.4L

If P is greater than 300kpa, then V = 0.6L

If P is equal to 300kpa, then 0.4L < V < 0.6L

At 100kpa, vf = 0.001043m/kg and vg = 1.693m³/kg

Level 1

v1 = 0.001043 + 0.2 x 1.693 = 0.33964

m = V1/v1 ⇔ 0.4/0.33964

m = 1.178kg

u1 = 417.36 + 0.2 x 2088.7 = 835.1kJ/kg

Level 3

v3 = 0.6/1.178 = 0.5095 < vG = 0.6058 at P3 is equal to 300kpa

NOTE: Piston does reach upper stops to reach saturated vapor

Level 4

v4 = v3 = 0.5095m³/kg = vG at P4

P4 = 361kpa, u4 = 2550.0kJ/kg

1W4 = 1W2 + 2W3 + 3W4 = 0 + 2W3 + 0

1W4 = P2 (V3 - V2) = 300 x (0.6 - 0.4) = 60kJ

1Q4 = m(u4 -u1) + 1W4 = 1.178(2550.0 - 835.1) + 60 = 2080kJ

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3 years ago