Answer:
It goes the crust mantle outer core and inner core. The crust is what we are standing on it has dirt, rock, stone, the mantle it has lots of silicate rocks and magnesium. The outer core has liquid nickel and iron and the inner core has solid metals
Answer:
1) The concentration of HCl = 0.1 M.
2) The table that can be used to organize the information correctly is C.
Explanation:
<u><em>1) The concentration of HCl:</em></u>
- We know that the no. of millimoles of the acid is equal to the no. of millimoles of the base at the neutralization point.
which means that: <em>(MV)HCl = (MV)NaOH,</em>
M of HCl = ??? M, V of HCl = 25.0 mL.
M of NaOH = 0.2 M, V of NaOH = 12.5 mL.
∴ M of HCl = (MV)NaOH/V of HCl = (0.2 M)(12.5 mL)/(25.0 mL) = 0.1 M.
<em>2) The table that can be used to organize the information correctly is C</em>
<em></em>
<em>Table A and B are the same and reported volume of HCl and NaOH is wrong.</em>
<em>Table C is right, contain the correct volumes and concentration of NaOH and missed the concentration of HCl which is 0.1 M.</em>
<em>Table D reported the volume and the concentration of HCl wrongly and also the concentration of NaOH. The data reported of HCl and NaOH is reversed.</em>
Answer:
No
Explanation:
Mass never changes unless you actually cut off or add to the object.
<u>Weight</u> changes based on gravity, but mass doesn't
There is no gaseous product when NaNO3 reacts with 6M HCl.
We must note that gas evolution is one of the signs that a chemical reaction has taken place. Hence, we must consider the options and look out for an option in which reaction with HCl does not lead to a gaseous product. This is the option that does not lead to evolution of a gas.
Let us consider the reaction; NaNO3(s) + HCl(aq) ---> NaCl(s) + HNO3(aq), there is no gaseous product hence NaNO3 does not result in gas evolution upon addition of 6M HCl.
Missing parts;
Addition of 6 M HCl to which substance will NOT result in gas evolution?
(A) Al
(B) Zn
(C) K2CO3
(D) NaNO3
Learn more about evolution of gas: brainly.com/question/2186340
