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Karolina [17]
3 years ago
5

The amount of energy it takes to remove an electron from an atom is

Chemistry
1 answer:
lara31 [8.8K]3 years ago
3 0
<span> the first ionization </span>energy<span> of an element is the </span>energy<span> needed to</span>remove<span> the outermost, or highest </span>energy<span>, </span>electron<span> from a neutral </span>atom<span> in the gas phase.</span>
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Choose the correct simplification of<br>x^12z^11/x^2z^4<br>​
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▹ Answer

<em>x¹⁰z¹⁵</em>

▹ Step-by-Step Explanation

x¹²z¹¹/x²z⁴

<u>Reduce</u>

x¹⁰z¹¹ * z⁴

<u>Calculate</u>

x¹⁰z¹⁵

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4 years ago
A and b are two gases that are mixed together: 2.50 mol a is mixed with 0.850 mol b. if the final pressure of the mixture is 1.7
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Partial pressure of gas A is 1.31 atm and that of gas B is 0.44 atm.

The partial pressure of a gas in a mixture can be calculated as

Pi = Xi x P

Where Pi is the partial pressure; Xi is mole fraction and P is the total pressure of the mixture.

Therefore we have Pa = Xa x P and Pb = Xb x P

Let us find Xa and Xb

Χa = mol a/ total moles = 2.50/(2.50+0.85) = 2.50/3.35 = 0.746

Xb = mol b/total moles = 0.85/(2.50+0.85) = 0.85/3.35 = 0.254

Total pressure P is given as 1.75 atm

Pa = Xa x P = 0.746 x 1.75 = 1.31atm

Partial pressure of gas A is 1.31 atm

Pb = Xb x P = 0.254 x 1.75 = 0.44atm

Partial pressure of gas B is 0.44 atm.

Learn more about Partial pressure here:

brainly.com/question/15302032

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How many lone pairs of electrons in lewis structure of CH3 OH
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