1 mole ------------ 6.02 x10²³ molecules
? mole ----------- 1.505 x10²³ molecules
1.505x10²³ / 6.02x10²³ => 0.25 moles
hope this helps!
Answer:
Both Options C and D are appropriate.
But I'd go with Option D since "Direct Air Capture" would eventually lead to "Ground Injection"
OPTION D.
Organic molecule. In particular, a carbohydrate.
A sample has 3.28 X 10^24 h atoms
so first we will find the moles of Hydrogen <span>by putting values in formula
that is
. moles </span>= no. of atoms/ Avogadro's no (NA) moles
= 5.446 we got this
<span> now the ratio of Carbon and Hydrogen is: C = H </span>
<span> 3 = 8 </span>
now multiply it with the moles
3/8 * 5.466 = 5.466 2.05 is the moles of C
. now:find the no of C atoms by this
<span> = moles X NA </span>
= 2.05 X 6.022 X 10^23
= 1.27 X10^2
now will find the mass of sampl:
so One mole of C3H8 = 3 moles of C 1/3 * 2.05 = 2.05 moles of C
<span> 0.68 moles of C3H8. </span>
now the mass of C3H8 = moles X molar mass mass of C3H8
which is = 0.68 X 44 =
<span> 30.2 grams of C3H8</span>
