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Inessa05 [86]
3 years ago
12

12. A runner at the start of a race generates 250 W of power as he accelerates to 5 m/s. If the runner has a mass of

Physics
1 answer:
Margaret [11]3 years ago
4 0
1/2 m/s2
30 Na




I hope this helps!
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A 30.0 g mass of iron at 24.5°C is heated to 45.0°C. The theoretical specific
diamong [38]

Answer:

276.135 J

Explanation:

Given that:

mass of Fe = 30.0 g

initial temperature = 24.5°C

final temperature = 45.0°C

specific heat of Fe = 0.449 J/g°C

We can determine the thermal energy added by using the formula;

Q = mcΔT

Q = 30.0g × 0.449 J/g°C × (45.0 - 24.5)°C

Q = 276.135 J

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How does the atmospheric temperature and size of inner planets compare with those of outer planets?
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The inner planets are rocky and have diameters of less than 13,000 kilometers. The outer planets include Jupiter, Saturn, Uranus, and Neptune. The smaller, inner planets include Mercury, Venus, Earth, and Mars. Inner planet's atmosphere is thin. (Mercury has no atmosphere). Outer Planets: Outer planets' atmosphere is very thick. The four inner planets, Mercury, Venus, Earth, and Mars, are warmer than the outer gas giants. However, the temperature of the planets does not follow a linear path from the Sun.

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Please give Brainliest!
6 0
2 years ago
Physics students study a piano being pulled across a room on a rug. They know that when it is at rest, it experiences a gravitat
Vanyuwa [196]
The static frictional force is greater than the kinetic frictional force, so the static frictional force is greater than 1200 N.
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Khaled said the North star is special because it appears all over the world and its changes position.
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2 years ago
If a galaxy has an apparent velocity of 2300 km/s, what is its distance if the Hubble constant is assumed to be 70 km/s/Mpc
prohojiy [21]

The distance of the galaxy is 32.86 Mpc.

Using the hubble law, v = H₀D where v = apparent velocity of galaxy = 2300 km/s, H = hubble constant = 70 km/s/Mpc and D = distance of galaxy.

Since we require the distance of the galaxy, we make D subject of the formula in the equation. So, we have

D = v/H₀

Substituting the values of the variables into the equation, we have

D = 2300 km/s ÷ 70 km/s/Mpc

D = 32.86 Mpc

So, the distance of the galaxy is 32.86 Mpc

Learn more about hubble law here:

brainly.com/question/18484687

4 0
2 years ago
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