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Diano4ka-milaya [45]
3 years ago
10

Imagine that a brown horse and a white horse cross to produce offspring whose coat is made up of some brown hair and some white

hairs. Which pattern of dominance is this an example of this
Physics
2 answers:
Lana71 [14]3 years ago
5 0

Answer:

Codominace

Explanation:

Codominance simply refers to a situation whereby there is an equal genetic effect of two parents on their offspring. It is a situation whereby neither of the alleles (i.e. a variant or type of gene) of the two parents can dominate, mask or prevent the expression of the other. Consequently, this will result on the equal expression of the two alleles for trait of the two parents.

Using the human example, there is a codominance when there is the ABO blood group which permits both alleles A and B to be expressed. As a result, if alleles A is inherited by a child from his father and he inherited allele B from his mother, it will result in him having AB as his blood type.

Therefore, the pattern of dominance is the example given in the question is called "codominance."

Fantom [35]3 years ago
4 0
<span>This is an example of Co dominance.

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Two identical cylindrical vessels with their bases at the same level each contain a liquid of density 1.23 g/cm3. The area of ea
motikmotik

Explanation:

Work done by gravity is given by the formula,

           W = \rho A (h_{1} - h)g (h - h_{2}) ......... (1)

It is known that when levels are same then height of the liquid is as follows.

           h = \frac{h_{1} + h_{2}}{2} ......... (2)

Putting value of equation (2) in equation (1) the overall formula will be as follows.

       W = \frac{1}{4} \rho gA(h_{1} - h_{2})^{2})

           = \frac{1}{4} \times 1.23 g/cm^{3} \times 9.80 m/s^{2} \times 3.89 \times 10^{-4} m^{2}(1.76 m - 0.993 m)^{2})

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Thus, we can conclude that the work done by the gravitational force in equalizing the levels when the two vessels are connected is 0.689 J.

3 0
3 years ago
An object is placed 18 cm in front of spherical mirror.if the image is formed at 4cm to the right of the mirror, calculate it's
ivolga24 [154]
1) Focal length

We can find the focal length of the mirror by using the mirror equation:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i} (1)
where 
f is the focal length
d_o is the distance of the object from the mirror
d_i is the distance of the image from the mirror

In this case, d_o = 18 cm, while d_i=-4 cm (the distance of the image should be taken as negative, because the image is to the right (behind) of the mirror, so it is virtual). If we use these data inside (1), we find the focal length of the mirror:
\frac{1}{f}= \frac{1}{18 cm}- \frac{1}{4 cm}=- \frac{7}{36 cm}
from which we find
f=- \frac{36}{7} cm=-5.1 cm

2) The mirror is convex: in fact, for the sign convention, a concave mirror has positive focal length while a convex mirror has negative focal length. In this case, the focal length is negative, so the mirror is convex.

3) The image is virtual, because it is behind the mirror and in fact we have taken its distance from the mirror as negative.

4) The radius of curvature of a mirror is twice its focal length, so for the mirror in our problem the radius of curvature is:
r=2f=2 \cdot 5.1 cm=10.2 cm
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Answer:

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