All categories

3 years ago

What is science? Science is observable, testable, replicable, reliable and flexible.

Physics

1 answer:

Ilia_Sergeevich [38]3 years ago

3 0

Answer:

Yes, the answer to the question is correct

You might be interested in

What distance will a car cover while uniformly accelerating from 12m/s to 26m/in 14 seconds

VikaD [51]

Answer:

Distance = 266m

Explanation:

6 0

3 years ago

A spring scale hung from the ceiling stretches by 5.2 cm when a 2.0 kg mass is hung from it. The 2.0 kg mass is removed and repl

pantera1 [17]

Physics - Damon, Wednesday, December 9, 2015 at 5:13am
F = k x

k = 2 g/6.1 cm

2.5g = (2g/6.1cm) x

x = 6.1 (2.5/2) cm

8 0

3 years ago

Read 2 more answers

A centrifuge in a medical laboratory rotates at an angular speed of 3,500 rev/min, clockwise (when viewed from above). When swit

Ratling [72]

Answer:

The magnitude of angular acceleration is $232.38\ rad/s^2$ .

Explanation:

Given that,

Initial angular velocity, $\omega_i=3500\ rev/min=366.5\ rad/s$

When it switched off, it comes o rest, $\omega_f=0$

Number of revolution, $\theta=46=289.02\ rad$

We need to find the magnitude of angular acceleration. It can be calculated using third equation of rotational kinematics as :

$\omega_f^2-\omega_i^2=2\alpha \theta\\\\\alpha =\dfrac{-\omega_i^2}{2\theta}\\\\\alpha =\dfrac{-(366.51)^2}{2\times 289.02}\\\\\alpha =-232.38\ rad/s^2$

So, the magnitude of angular acceleration is $232.38\ rad/s^2$ . Hence, this is the required solution.

6 0

3 years ago

A farmer had 15 sheep, and all but 8 died. How many are left?

Troyanec [42]

So he has 7 sheepleft if i did it correctly
15-8=7

3 0

2 years ago

Read 2 more answers

A 72.0 kg stuntman jumps from a moving car to a 2.50 kg skateboard at rest. If the velocity of the car is 15.0 m/s to the east w

yawa3891 [41]

Answer:

B 14.5 m/s to the east

Explanation:

We can solve this problem by using the law of conservation of momentum.

In fact, if the system is isolated, the total momentum of the system must be conserved.

Here the total momentum before the stuntman reaches the skateboard is:

$p_i = Mv$

where

M = 72.0 kg is the mass of the stuntman

v = 15.0 m/s is his initial velocity (to the east)

The total momentum after the stuntmen reaches the skateboard is:

$p_f = (M+m)v'$

where

m = 2.50 kg is the mass of the skateboard

v' is the final velocity of the stuntman and the skateboard

Since momentum must be conserved, we have

$p_i = p_f\\Mv=(M+m)v'$

And solvign for v',

$v'=\frac{Mv}{M+m}=\frac{(72.0)(15.0)}{(72.0+2.50)}=14.5 m/s$

And since the sign is the same as v, the direction is the same (to the east).

7 0

3 years ago