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Dimas [21]
3 years ago
14

Three forces act on an object. a 3 n force acts due east and a 8 n force acts due north. if the net force on the object is zero,

what is the magnitude of the third force?"
Physics
1 answer:
Bingel [31]3 years ago
6 0

The third force C is in the opposite direction of the sum of the first two forces, A+B, but the magnitude is the same as A+B  

Since A & B are at right angles we can just use Pythagoras and trig:  

A+B magnitude = sqrt(6^2 + 3^2) = 6.71  

A+B angle = arctan(6/3) deg north of east = 63.4 deg (first quadrant)

So C magnitude = 6.71 (same as A+B)  

[C angle = 63.4 deg south of west (third quadrant) = -180+63.4 deg polar = -116.6 deg

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An object is lifted from the surface of a spherical planet to an altitude equal to the radius of the planet.  

As a result, the object's <em>mass remains the same</em>, and its <em>weight decreases</em> to 1/4 of whatever it is when the object is on the planet's surface.

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An organism is composed of several organ systems. Often, the different organ systems work together towards a common purpose. For
Gemiola [76]

Answer:

Skeletal system, muscular system

Explanation:

Skeletal system:

bones

Muscular system:

muscles

Together, they work together and create the musculoskeletal system.

4 0
3 years ago
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A 3.5 kg object moving in two dimensions initially has a velocity v1 = (12.0 i^ + 22.0 j^) m/s. A net force F then acts on the o
lys-0071 [83]

Answer:

The work done by the force is 820.745 joules.

Explanation:

Let suppose that changes in potential energy can be neglected. According to the Work-Energy Theorem, an external conservative force generates a change in the state of motion of the object, that is a change in kinetic energy. This phenomenon is describe by the following mathematical model:

K_{1} + W_{F} = K_{2}

Where:

W_{F} - Work done by the external force, measured in joules.

K_{1}, K_{2} - Translational potential energy, measured in joules.

The work done by the external force is now cleared within:

W_{F} = K_{2} - K_{1}

After using the definition of translational kinetic energy, the previous expression is now expanded as a function of mass and initial and final speeds of the object:

W_{F} = \frac{1}{2}\cdot m \cdot (v_{2}^{2}-v_{1}^{2})

Where:

m - Mass of the object, measured in kilograms.

v_{1}, v_{2} - Initial and final speeds of the object, measured in meters per second.

Now, each speed is the magnitude of respective velocity vector:

Initial velocity

v_{1} = \sqrt{v_{1,x}^{2}+v_{1,y}^{2}}

v_{1} = \sqrt{\left(12\,\frac{m}{s} \right)^{2}+\left(22\,\frac{m}{s} \right)^{2}}

v_{1} \approx 25.060\,\frac{m}{s}

Final velocity

v_{2} = \sqrt{v_{2,x}^{2}+v_{2,y}^{2}}

v_{2} = \sqrt{\left(16\,\frac{m}{s} \right)^{2}+\left(29\,\frac{m}{s} \right)^{2}}

v_{2} \approx 33.121\,\frac{m}{s}

Finally, if m = 3.5\,kg, v_{1} \approx 25.060\,\frac{m}{s} and v_{2} \approx 33.121\,\frac{m}{s}, then the work done by the force is:

W_{F} = \frac{1}{2}\cdot (3.5\,kg)\cdot \left[\left(33.121\,\frac{m}{s} \right)^{2}-\left(25.060\,\frac{m}{s} \right)^{2}\right]

W_{F} = 820.745\,J

The work done by the force is 820.745 joules.

6 0
3 years ago
A decrease in the magnitude of velocity is called
vagabundo [1.1K]
Any change in the speed or direction of motion is called "acceleration". You'll hear "deceleration" used for slowing down but that's not technically correct.
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The higher the objects " ? ", the more kinetic energy
natita [175]

Answer:

yes

Explanation:

can i get brainlest pls

7 0
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