A ball is dropped from a height of 20 meters. At what height does the ball have a velocity of 10 meters/second?
1 answer:
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The balloon's volume at 35°C : V₂=31.01 L
<h3>Further explanation</h3>Given
T₁ = 25°C+273 = 298 K
V₁ = 30 L
T₂ = 35 °C + 273 = 308 K
Required
The new volume (V₂)
Solution
Charles's Law
When the gas pressure is kept constant, the gas volume is proportional to the temperature
Input the value :
V₂=(V₁.T₂)/T₁
V₂=(30 x 308)/298
V₂=31.01 L