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notsponge [240]
2 years ago
13

The sum of two component vectors is referred to as the

Physics
1 answer:
blondinia [14]2 years ago
8 0
Resultant is the correct answer!
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London lives 1200 meters south of Chick-fil-A and is thinking about going there for lunch. When she is ready to leave, she reali
saul85 [17]

Answer:

  1750 m

Explanation:

The distance traveled is the 750 meters to the Aunt's house plus the 1000 m from there to Chick-fil-A.

  750 +1000 = 1750 . . . meters traveled

6 0
2 years ago
Suppose that you are headed toward a plateau 55 meters high. If the angle of elevation to the top of the plateau is 40degrees​,
Iteru [2.4K]

Answer:

x=65.55m

Explanation:

Let x be the distance to the shore

From trigonometry properties:

tan(40^{o} )=\frac{55m}{x} \\x=\frac{55m}{tan(40^{o} )} \\x=65.55m

3 0
3 years ago
A man pulls on his dog's leash to keep him from running after a bicycle. Which term best describes this example? Select one: A.
madreJ [45]
C. Negative force. The dog isn't going to learn that way.

6 0
3 years ago
A soccer ball kicked with a force of 12.5 N accelerates at 6.2 m/s’ to the right. What is the mass of the ball? Answer in units
stepladder [879]

Answer:

m = 2.01[kg]

Explanation:

This problem can be solved using Newton's second law which tells us that the force applied on a body is equal to the product of mass by acceleration.

F =m*a

where:

F = force = 12.5 [N]

m = mass [kg]

a = acceleration = 6.2 [m/s²]

12.5=m*6.2\\m = 2.01[kg]

3 0
3 years ago
A new planet is discovered beyond Pluto at a mean distance to the sun of 4004 million miles. Using Kepler's third law, determine
AVprozaik [17]

Answer:

103239.89 days

Explanation:

Kepler's third law states that the square of the orbital period of a planet is directly proportional to the cube of the semi-major axis of its orbit.

                               a³ / T² = 7.496 × 10⁻⁶  (a.u.³/days²)

where,

a is the distance of the semi-major axis in a.u

T is the orbit time in days

Converting the mean distance of the new planet to astronomical unit (a.u.)

                       1 a.u = 9.296 × 10⁷ miles        

                                      \frac{4004 * 10^{6}}{9.296 * 10^{7}}  =  43.07\ a.u.

Substituting the values into Kepler's third law equation;

                                    \frac{(43.07)^{3}}{T^{2}}  =  7.496 * 10^{-6}  

                                    T^{2} = \frac{(43.07)^{3}}{7.496 * 10^{-6}} (days)²

                                    T^{2} = \sqrt{\frac{(43.07)^{3}}{7.496 * 10^{-6}}}

                                    T = 103239.89 days

An estimate time T for the new planet to travel around the sun in an orbit is 103239.89 days

7 0
3 years ago
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