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Morgarella [4.7K]
3 years ago
12

A substance that Connor be broken down into simplersubstance by ordinary chemical means

Physics
1 answer:
Nana76 [90]3 years ago
8 0

Answer:

An element

Explanation:

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A high-pass filter consists of a 1.66 μF capacitor in series with a 80.0 Ω resistor. The circuit is driven by an AC source with
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Explanation:

Given that,

Capacitor C=1.66\ \mu F

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f_{c}=\dfrac{1}{2\pi\times80.0\times1.66\times10^{-6}}

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(B). We need to calculate the V_{R} when f = \dfrac{1}{2f_{c}}

Using formula of  V_{R}

V_{R}=V_{0}(\dfrac{R}{\sqrt{R^2+(\dfrac{1}{2\pi fC})^2}})

Put the value into the formula

V_{R}=5.10\times(\dfrac{80.0}{\sqrt{(80.0)^2+(\dfrac{1}{2\pi\times\dfrac{1}{2}\times1198.45\times1.66\times10^{-6}})^2}})

V_{R}=2.280\ Volt

(C). We need to calculate the V_{R} when f = f_{c}

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V_{R}=3.606\ Volt

(D). We need to calculate the V_{R} when f = 2f_{c}

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V_{R}=5.10\times(\dfrac{80.0}{\sqrt{(80.0)^2+(\dfrac{1}{2\pi\times2\times1198.45\times1.66\times10^{-6}})^2}})

V_{R}=4.561\ Volt

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4 years ago
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Answer:

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Answer:

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