Answer:

Explanation:
Given that;
I₀ = 9.55 A
f = 359 cycles/s
b = 72.2 cm
c = 32.5 cm
a = 80.2 cm
Using the formula;

where;



Replacing our values into above equation; we have:



Then the
is calculated as:



A) We balance the masses: 4(1.00728) vs 4.0015 + 2(0.00055)4.02912 vs. 4.0026This shows a "reduced mass" of 4.02912 - 4.0026 = 0.02652 amu. This is also equivalent to 0.02652/6.02E23 = 4.41E-26 g = 4.41E-29 kg.
b) Using E = mc^2, where c is the speed of light, multiplying 4.41E-29 kg by (3E8 m/s)^2 gives 3.96E-12 J of energy.
c) Since in the original equation, there is only 1 helium atom, we multiply the energy result in b) by 9.21E19 to get 3.65E8 J of energy, or 365 MJ of energy.
Acceleration is measured in m/s².
Answer: m/s²