Considering the angle a by cosine rule
11^2 =7 ^2 +15^2 - 2(7)(15)cos(a)
When you do the maths,
Cos(a) =153/210 =0.729
a= cos inverse of 0.729
a=43 degrees
Considering angle b
7^2=15^2 +11^2 -2(11)(15) cos(b)
This will result in cos(b) =297/330=0.9
b= cos inverse of 0.9 = 25.8 degrees
Considering angle c
15^2=7^2 +11^2 - 2(11)(7) cos(c)
Cos(c) will be = -55/154 = -0.357
c= cos inverse of -0.357=110.9
Comparing the angles a,b and c,
C is the largest size in the triangle with an angle of 110.9 degrees
Am I right please ??
Answer:
Step-by-step explanation:
a)
- 6ˣ = 1/216
- 6ˣ = 1/6³
- 6ˣ = 6⁻³
- x = -3
b)
- 5⁻³ × 2⁻¹ =
- 1/5³ × 1/2 =
- 1/(125×2) =
- 1/250 or 0.004
We have the following table:
545-534.2 = 10.8
545-556.4 = -11.4
545-554.0 = -9
545-535.3 = 9.7
write them as a positive and negative rational numbers
positive:
9.7 = 9 7/10
10.8 = 10 4/5
negative:
-11.4 = -11 2/5
-9 = -9
the differences from least to greatest
-11 2/5
-9
9 7/10
10 4/5
Answer:
sorry but you're gonna need to add more info to this question to get an answer
