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otez555 [7]
2 years ago
12

Write down the factors on which moment depends upon ?​

Physics
1 answer:
timurjin [86]2 years ago
5 0

Answer:

  • The size of a force
  • The perpendicular distance from the pivot the line of action of force

Explanation:

Factors that affect the moment of a force are;

  • The size of a force
  • The perpendicular distance from the pivot the line of action of force

The magnitude of force applied is directly proportional to the moment of force in that for a perpendicular distance d, increased in force applied will result to a higher moment of force. When the perpendicular distance from the pivot is decreased while the force applied remains constant, the moment of force decreases.

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An object moving at 15 m/s slows uniformly at a rate of 2.0 m/s each second for 5.0 s. What is its final speed?​
NeX [460]
Hey there!

We are given ,

Acceleration, a = -2m/s^2

Initial velocity , u = 15m/s

Time , t = 5 seconds

We know that ,
V=u+at

Now , final speed ,

V = 15+(-2)(5)

V = 15-10

V = 5 m/s -> final speed

Hope this helps you dear :)
Have a good day <3

8 0
2 years ago
Sound travels faster in: steel water sir
alukav5142 [94]
Sound travels better in water
8 0
3 years ago
A dentist causes the bit of a high-speed drill to accelerate from an angular speed of 1.10 104 rad/s to an angular speed of 3.14
Anestetic [448]

Answer:

3.63 s

Explanation:

We can solve the problem by using the equivalent SUVAT equations for the angular motion.

To find the angular acceleration, we can use the following equation:

\omega_f^2 - \omega_i ^2 =2 \alpha \theta

where

\omega_f = 3.14\cdot 10^4 rad/s is the final angular speed

\omega_i = 1.10 \cdot 10^4 rad/s is the initial angular speed

\theta= 2.00 \cdot 10^4 rad is the angular distance covered

\alpha is the angular acceleration

Re-arranging the formula, we can find \alpha:

\alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}=\frac{(3.14\cdot 10^4 rad/s)^2-(1.10\cdot 10^4 rad/s)^2}{2(2.00\cdot 10^4 rad)}=2.16\cdot 10^4 rad/s^2

Now we want to know the time the bit takes starting from rest to reach a speed of \omega_f=7.85\cdot 10^4 rad/s. So, we can use the following equation:

\alpha = \frac{\omega_f-\omega_i}{t}

where:

\alpha=2.16\cdot 10^4 rad/s^2 is the angular acceleration

\omega_f = 7.85\cdot 10^4 rad/s is the final speed

\omega_i = 0 is the initial speed

t is the time

Re-arranging the equation, we can find the time:

t=\frac{\omega_f-\omega_i}{\alpha}=\frac{7.85\cdot 10^4 rad/s-0}{2.16\cdot 10^4 rad/s^2}=3.63 s

4 0
3 years ago
Read 2 more answers
The _____ of a wave is the number of wave cycles per second. this quantity is given the symbol ν and has units of s–1 or _____.
Fynjy0 [20]

The frequency of a wave is the number of wave cycles per second. this quantity is given the symbol ν and has units of s^–1 or hertz.

What is a wave ?

A wave is a dynamic disturbance of one or more quantities that propagates through time. When waves oscillate frequently around an equilibrium value at a certain frequency, they are said to be periodic.

What is a wave cycle ?

The wavelength is the measured distance in meters between two waves' peaks or troughs, which is referred to as a wave cycle. It's crucial to remember that the distance from peak to peak equals the distance from trough to trough. The length of time it takes a wave to complete one cycle is known as the wave's period.

Learn more about waves here:-

brainly.com/question/3639648

#SPJ4

8 0
1 year ago
This system consists of a marble rolling down a ramp. Assume the mass of the marble is 5.0 g. Decide what would be needed to mea
Nina [5.8K]

Answer: v = √2.g.h

Explanation:

If we assume that the marble can be approximated by a point mass, and that it starts from rest at a height h, at that moment, all the energy of the system will be gravitational potential energy, that can be written as follows:

U₁ = m. g. h

As we know m, and g is a constant equal to 9.8 m/s², we will need to measure  the height h, either directly, or in an indirect way from the value of the angle that the ramp does with the horizontal, and the measured value of  the distance travelled along the ramp, x.

So, we could write U₁ as follows:

U₁ = m . g. x. sin θ

Now, at the bottom of the ramp, neglecting fricition, all this potential energy must become kinetic energy, as follows:

U₁ = K₂ ⇒ mgh = 1/2 m(v₂)²

Simplifying and solving for v₂ (the speed of the marble at the top of the bottom), we have:

v₂ = √2.g.h

Once the marble has reached to the bottom of the ramp, it has no more net  external forces acting on it (neglecting friction), it must continue moving at constant speed, equal to v₂.

This value can be measured easily, measuring the displacement between 2 points, and the time used to pass between those points, and computing v₂ as follows:

v₂ = Δx / Δt

If the measured value is different to the one calcultated (beyond the expected experimental error) this means that the friction was not so negligible.

5 0
3 years ago
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