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otez555 [7]
3 years ago
12

Write down the factors on which moment depends upon ?​

Physics
1 answer:
timurjin [86]3 years ago
5 0

Answer:

  • The size of a force
  • The perpendicular distance from the pivot the line of action of force

Explanation:

Factors that affect the moment of a force are;

  • The size of a force
  • The perpendicular distance from the pivot the line of action of force

The magnitude of force applied is directly proportional to the moment of force in that for a perpendicular distance d, increased in force applied will result to a higher moment of force. When the perpendicular distance from the pivot is decreased while the force applied remains constant, the moment of force decreases.

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poizon [28]

Answer:

Because they have already made an impact within our atmosphere

6 0
3 years ago
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These UV photons can break chemical bonds in your skin to cause sunburn—a form of radiation damage. If the 305 nm radiation prov
astraxan [27]

Answer:

energy = 391.902 kJ /mol

Explanation:

given data

wavelength = 305 nm = 305 ×10^{-9} m

to find out

average energy

solution

we know speed of light is 3 ×10^{8} m/s

so we find frequency here first by speed of light formyla

speed = wavelength × frequency

3 ×10^{8}  = 305 ×10^{-9} × frequency

frequency = 9.8360 ×10^{14} s^{-1}

so energy is

energy = hf

here h = 6.62 ×10^{-34} J-s

so

energy =  6.62 ×10^{-34}  × 9.8360 ×10^{14}

energy = 6.51 ×10^{-14} J

so

energy = 6.51 ×10^{-14}  × \frac{6.02*10^23}{1000} kJ/mol

energy = 391.902 kJ /mol

7 0
4 years ago
The weight of a person is 500N and his foot imprint area is 0.5m^2.Calculate the total pressure exerted by person when he stands
Ghella [55]

Answer:

Pressure on both feet will be 500N/m^2  

Explanation:

Weight of the person F = 500 N

Area of foot print A=0.5m^2

Area of both the foot A=2\times 0.5=1m^2

We have to find pressure on both the feet

Pressure is equal to ratio of force and area

So pressure P=\frac{F}{A}

P=\frac{500}{1}=500N/m^2

So the pressure on both feet will be 500N/m^2 when person stands on both feet.

7 0
3 years ago
A car rounds a curve while maintaining a constant speed. Is there a net force on the car as it rounds the curve?
Nesterboy [21]

Answer:

Yes, Centripetal Force acts on the Car.

Explanation:

When a car undergoes a circular motion, a centripetal force acts onto it.

Centripetal Force = [m*(v^2)]/R , where

  • R is the radius of curve
  • v is the constant speed
  • m is the mass of the car
4 0
4 years ago
Similarities and differences between<br> distance Time graph and velocity time<br> graph?
egoroff_w [7]

Answer:

Similarity: >>Time is independent variable and such is on the x-axis. ... >>Distance time graph tells you how much distance you have travelled, while velocity time graph tells you your acceleration.  The difference between them is that the velocity-time graph reveals the speed of an object (and whether it is slowing down or speeding up), while the position-time graph describes the motion of an object over a period of time.

Explanation:

4 0
3 years ago
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