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otez555 [7]
3 years ago
12

Write down the factors on which moment depends upon ?​

Physics
1 answer:
timurjin [86]3 years ago
5 0

Answer:

  • The size of a force
  • The perpendicular distance from the pivot the line of action of force

Explanation:

Factors that affect the moment of a force are;

  • The size of a force
  • The perpendicular distance from the pivot the line of action of force

The magnitude of force applied is directly proportional to the moment of force in that for a perpendicular distance d, increased in force applied will result to a higher moment of force. When the perpendicular distance from the pivot is decreased while the force applied remains constant, the moment of force decreases.

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The height of a projectile t seconds after it is launched straight up in the air is given by f (t )equals negative 16 t squared
velikii [3]

Answer:

\displaystyle a(5)=-32

Explanation:

<u>Instant Acceleration</u>

The kinetic magnitudes are usually related as scalar or vector equations. By doing so, we are assuming the acceleration is constant over time. But when the acceleration is variable, the relations are in the form of calculus equations, specifically using derivatives and/or integrals.

Let f(t) be the distance traveled by an object as a function of the time t. The instant speed v(t) is defined as:

\displaystyle v(t)=\frac{df}{dt}

And the acceleration is

\displaystyle a(t)=\frac{dv}{dt}

Or equivalently

\displaystyle a(t)=\frac{d^2f}{d^2t}

The given height of a projectile is

f(t)=-16t^2 +238t+3

Let's compute the speed

\displaystyle v(t)=-32t+238

And the acceleration

\displaystyle a(t)=-32

It's a constant value regardless of the time t, thus

\boxed{\displaystyle a(5)=-32}

3 0
3 years ago
What is the formula for the moment of inertia of the person/single particle rotating in a circle? (Give these values with a subs
Ann [662]

Moment of inertia of single particle rotating in circle is I1 = 1/2 (m*r^2)

The value of the moment of inertia when the person is on the edge of the merry-go-round is I2=1/3 (m*L^2)

Moment of Inertia refers to:

  • the quantity expressed by the body resisting angular acceleration.
  • It the sum of the product of the mass of every particle with its square of a distance from the axis of rotation.

The moment of inertia of single particle rotating in a circle I1 = 1/2 (m*r^2)

here We note that the,

In the formula, r being the distance from the point particle to the axis of rotation and m being the mass of disk.

The value of the moment of inertia when the person is on the edge of the merry-go-round is determined with parallel-axis theorem:

I(edge) = I (center of mass) + md^2

d be the distance from an axis through the object’s center of mass to a new axis.

I2(edge) = 1/3 (m*L^2)

learn more about moment of Inertia here:

<u>brainly.com/question/14226368</u>

#SPJ4

7 0
2 years ago
What is the kind of energy that comes from movement?
Sergio [31]

Answer:

motion energy

Explanation:

motion wnergy is the sum of potential and kinetic energy

4 0
3 years ago
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If revenue is $3,000 and operating expenses are $4,000, cash flow equals _____. -$1,000 $1,000 -$7,000 $7,000
valkas [14]

Answer:

-$1,000

Explanation:

$3000 - $4000

4 0
3 years ago
What vibrates in an EM wave
AlladinOne [14]

Answer:magnetic and electric fields

Explanation:

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