Which of the following parallel plate diagrams would have the greatest electric fields between them?
1 answer:
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Answer:
Explanation:
Given that:
Charge (q) on the particle = 3 × 10⁻⁸ C
mass (m) of the particle = 6 × 10⁻⁹ kg
at a distance x = 15 cm , the velocity in the plate = 900 m/s²
For the square plate, the surface charged density σ = -8 × 10⁻⁶ C/m²
To start with calculating the electric field as a result of the square plate; we use the formula;
On the square plate; The electric force F = Eq
The acceleration
For the particle, the velocity at distance x = 7 m can be calculated by using the formula:
From the calculation, we realize that the charge acting between the particle and the plate is said to be "opposite".
Hence, the force is an attractive force.
Similarly, there is a gradual increase exhibited by the velocity of the particle.
Therefore, the particles get to the detector, but the detector failed to get detect due to the velocity which is greater than 1000 m/s.
Decreases
Explanation:
The force of attraction between two objects will decrease as the distance between them increases.
This is in compliance with newtons law of universal gravitation.
The force of attraction between the two bodies is a gravitational force.
According to newton's law of universal gravitation "the force of attraction between two bodies is directly proportional to the product of their masses and inversely proportional to the square of the distances between them".
We see that from the last statement, the force of attraction between is inversely proportional to the square of the distances between them.
F ∞
r is the distance between them.
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Universal gravitation brainly.com/question/1724648
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