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Mnenie [13.5K]
3 years ago
12

3. What is the power of a derby race car that uses a 50 N force to travel 20 meters in 10 seconds?

Physics
1 answer:
makkiz [27]3 years ago
7 0
I think it is B. 100 W
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Kinetic energy is the energy an object has due to its
lara31 [8.8K]

Answer:

potential energy or stored energy

Explanation:

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3 years ago
Read 2 more answers
A 36.3 kg cart has a velocity of 3 m/s. How much kinetic energy does the object have?
uysha [10]

Answer:

163.35

__________________________________________________________

<u>We are given:</u>

Mass of the object (m) = 36.3 kg

Velocity of the object (v) = 3 m/s

<u>Kinetic Energy of the object:</u>

We know that:

Kinetic Energy = 1/2(mv²)

KE = 1/2(36.3)(3)²            [replacing the variables with the given values]

KE = 18.15 * 9

KE = 163.35 Joules

Hence, the cart has a Kinetic Energy of 163.35 Joules

7 0
2 years ago
A car travels 60 miles due West first then turns back and travels 120 miles due East in 3 hours. What is...
ella [17]

Answer:

<h2>A. 180 miles</h2><h2>B. 60 miles</h2><h2 />

Explanation:

In this problem, we are required to solve for the total distance that the car travelled. and the displacement

A) the distance travelled by car

this can be gotten by summing all the distances the car has travelled.

i,e total distance= 60 miles+120 miles

total distance= 180 miles

B) the displacement of the car

the displacement can be gotten by  subtracting the final distance from the initial distance

final distance = 120 miles

initial distance= 60 miles

displacement= 120-60= 60 miles

7 0
3 years ago
Whats the kinetic energy of an object that has a mass of 12 kilograms and moves with a velocity of 10 m/s
Vesnalui [34]

Answer:

600J

Explanation:

1/2mv^2

1/2(12)(10^2)

6(100)

600

7 0
3 years ago
An ice cube at 0c was dropped into 30.0 g of water in a cup at 45.0c. at the instant that all of the ice was melted, the tempera
Ede4ka [16]
The amount of heat given by the water to the block of ice can be calculated by using
Q=m_w C_{sw} \Delta T_w
where 
m_w = 30 g is the mass of the water
C_{sw}=4.18 J/(g ^{\circ}C) is the specific heat capacity of water
\Delta T_w = 45.0^{\circ}-19.5^{\circ}C = 20.5^{\circ}C is the variation of temperature of the water.

Using these numbers, we find
Q=(30 g)(4.18 J/(g^{\circ}C))(20.5^{\circ}C)=2571 J

This is the amount of heat released by the water, but this is exactly equal to the amount of heat absorbed by the ice, used to melt it into water according to the formula:
Q = m_i L_f
where m_i is the mass of the ice while L_f =334 J/g is the specific latent heat of fusion of the ice.
Re-arranging this formula and using the heat Q that we found previously, we can calculate the mass of the ice:
m_i =  \frac{Q}{L_f}= \frac{2571 J}{334 J/g} =7.7 g
3 0
2 years ago
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