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rewona [7]
1 year ago
10

If you see an object rotating, is there necessarily a net torque acting on it?

Physics
1 answer:
mina [271]1 year ago
7 0

There need not necessarily be net torque acting on a rotating object.

<h3>What is angular acceleration?</h3>
  • Angular acceleration is the term used to describe the temporal pace at which angular velocity varies. Radians per second is the accepted unit of measurement. Consequently, = d d t. Angular acceleration is also known as rotational acceleration.
  • Angular acceleration can be calculated by dividing the angular velocity by the acceleration duration. (t). Use pi instead, or the drive speed (n) divided by the acceleration time (t) multiplied by 30. The usual SI unit for the rotational acceleration that results from this equation is radians per second squared (Rad/sec2).

Is there always a net torque acting on an object when you perceive it rotating?

  • Torque, force, and angular acceleration are the ideas applied to this problem's solution.
  • Use the notion of force to first determine whether there is net torque operating on a rotating body.
  • Then, using the idea of angular acceleration, determine whether there is net torque operating on a rotating body.
  • Torque is the measure of the amount of force that causes a body to accelerate in one direction. It is often referred to as the rotational force of a body.

Step: 1

  • The torque of a spinning body can be zero if an object's total amount of forces acting on it is zero or if the object is in rotational equilibrium.
  • A vector quantity is a torque. There won't be any net torque acting on the body if the forces causing the rotation are equal and opposing.
  • Using the idea of angular acceleration, determine whether there is net torque operating on a rotating body.
  • The body's angular acceleration will be 0 if it is rotating with constant angular speed. The net torque is 0 for a body with 0 angular acceleration.

There need not necessarily be net torque acting on a rotating object.

To learn more about angular acceleration, refer to:

brainly.com/question/20912191

#SPJ4

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How does proximity to oceans affect Temperatures and<br> rainfall amounts?
vampirchik [111]

Answer:

Because they absorb and emit heat more steadily than land, oceans help moderate temperatures in coastal areas, making winters warmer and summers cooler. Winds that blow in from across the oceans bring more rainfall and higher humidity.

Explanation:

4 0
2 years ago
A world class sprinter is travelling with speed 12.0 m/s at the end of a 100 meter race. Suppose he decelerates at the rate of 2
Solnce55 [7]

Answer:

after 6 second it will stop

he travel 36 m to stop

Explanation:

given data

speed = 12 m/s

distance = 100 m

decelerates rate = 2.00 m/s²

so acceleration a = - 2.00 m/s²

to find out

how long does it take to stop and how far does he travel

solution

we will apply here first equation of motion that is

v = u + at   ......1

here u is speed 12 and v is 0 because we stop finally

put here all value in equation 1

0 = 12 + (-2) t

t = 6 s

so after 6 second it will stop

and

for distance we apply equation of motion

v²-u² = 2×a×s  ..........2

here v is 0 u is 12 and a is -2 and find distance s

put all value in equation 2

0-12² = 2×(-2)×s

s = 36 m

so  he travel 36 m to stop

3 0
2 years ago
We have seen that when you generate a wave on a stretched spring, as long as the medium doesn’t change (that is, the tension and
TiliK225 [7]

Answer:

No, the acceleration is not always zero.

Explanation:

It does not mean that the acceleration of the particle is zero.

The velocity of wave is different from the velocity of particle.

The acceleration of wave is different from the acceleration of particle.

the acceleration of the particle is given by

a =- w^2 y

where, w is the angular frequency and y is the displacement from the mean position.

So, the acceleration is zero at mean position only and it varies as the position changes.  

6 0
2 years ago
Two Earth satellites, A and B, each of mass m, are to be launched into circular orbits about Earth’s center. Satellite A is to o
Vera_Pavlovna [14]

Answer:

Explanation:

Orbital radius of satellite A , Ra = 6370 + 6370 = 12740 km

Orbital radius of satellite B , Rb = 6370 + 19110 = 25480 km

Orbital potential energy of a satellite = - GMm / r where G is gravitational constant , M is mass of the earth and m is mass of the satellite

Orbital potential energy of a satellite A = - GMm / Ra

Orbital potential energy of a satellite B = - GMm / Rb

PE of satellite B /PE of satellite A

=  Ra / Rb

= 12740 / 25480

= 1 / 2

b ) Kinetic energy of a satellite is half the potential energy with positive value , so ratio of their kinetic energy will also be same

KE of satellite B /KE of satellite A

= 1 / 2

c ) Total energy will be as follows

Total energy = - PE + KE

- P E + PE/2

= - PE /2

Total energy of satellite B / Total energy of A

= 1 / 2

Satellite B will have greater total energy because its negative value is less.

5 0
2 years ago
What is a small portable device that counts every step taken throughout the day?
Valentin [98]

Answer: B

Explanation: i learned it last year

7 0
1 year ago
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