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rewona [7]
1 year ago
10

If you see an object rotating, is there necessarily a net torque acting on it?

Physics
1 answer:
mina [271]1 year ago
7 0

There need not necessarily be net torque acting on a rotating object.

<h3>What is angular acceleration?</h3>
  • Angular acceleration is the term used to describe the temporal pace at which angular velocity varies. Radians per second is the accepted unit of measurement. Consequently, = d d t. Angular acceleration is also known as rotational acceleration.
  • Angular acceleration can be calculated by dividing the angular velocity by the acceleration duration. (t). Use pi instead, or the drive speed (n) divided by the acceleration time (t) multiplied by 30. The usual SI unit for the rotational acceleration that results from this equation is radians per second squared (Rad/sec2).

Is there always a net torque acting on an object when you perceive it rotating?

  • Torque, force, and angular acceleration are the ideas applied to this problem's solution.
  • Use the notion of force to first determine whether there is net torque operating on a rotating body.
  • Then, using the idea of angular acceleration, determine whether there is net torque operating on a rotating body.
  • Torque is the measure of the amount of force that causes a body to accelerate in one direction. It is often referred to as the rotational force of a body.

Step: 1

  • The torque of a spinning body can be zero if an object's total amount of forces acting on it is zero or if the object is in rotational equilibrium.
  • A vector quantity is a torque. There won't be any net torque acting on the body if the forces causing the rotation are equal and opposing.
  • Using the idea of angular acceleration, determine whether there is net torque operating on a rotating body.
  • The body's angular acceleration will be 0 if it is rotating with constant angular speed. The net torque is 0 for a body with 0 angular acceleration.

There need not necessarily be net torque acting on a rotating object.

To learn more about angular acceleration, refer to:

brainly.com/question/20912191

#SPJ4

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Answer:

Exercise 1;

The centripetal acceleration is approximately 94.52 m/s²

Explanation:

1) The given parameters are;

The diameter of the circle = 8 cm = 0.08 m

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The speed of motion = 7 km/h = 1.944444 m/s

The centripetal acceleration = v²/r = 1.944444²/0.04 ≈ 94.52 m/s²

The centripetal acceleration ≈ 94.52 m/s²

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<span>(B) </span>
<span>(1/2)(8.33 rev/s²)(3.0 s)² = 37.5 rev </span>

<span>(C) </span>
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3 0
3 years ago
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A vacuum cleaner produces sound with a measured sound level of 75.0 dB. (a) What is the intensity of this sound in W/m2? W/m2 (b
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Answer:

Part a)

I = 3.16 \times 10^{-5} W/m^2

Part b)

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Explanation:

Part a)

Level of sound = 75 dB

now we know that

L = 10 Log\frac{I}{I_0}

here we know that

I_0 = 10^{-12} W/m^2

now we have

75 = 10 Log(\frac{I}{10^{-12}})

I = 3.16 \times 10^{-5} W/m^2

Part b)

Intensity of sound wave is given as

I = \frac{1}{2}\rho A^2\omega^2 c

here we know that

A = \frac{P_o}{Bk}

so we have

I = \frac{1}{2}\rho(\frac{P_o}{Bk})^2\omega^2 c

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now we know

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B = 1.4 \times 10^5 Pa

now we have

3.16 \times 10^{-5} = \frac{1}{2}(1.2)P_o^2\frac{340^3}{(1.4\times 10^5)^2}

P_o = 0.162 Pa

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