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Kryger [21]
3 years ago
11

A chemist has to prepare 750.0 mL of a 0.200 M KNO3(aq) solution. What mass, in grams, of potassium nitrate (formula mass 101.11

g/mol) would they use
Chemistry
1 answer:
Hunter-Best [27]3 years ago
3 0

Answer:

They would use 15.17 g KNO₃.

Explanation:

To solve this problem first we <u>calculate the number of KNO₃ moles that would be in the solution</u>, multiplying the concentration times the volume:

  • moles = Concentration * Volume

750 mL ⇒ 750 / 1000 = 0.750 L

  • 0.200 M * 0.750 L = 0.150 mol KNO₃

Then we<u> convert moles of KNO₃ to grams</u>, using its <em>molar mass:</em>

  • 0.150 mol KNO₃ * 101.11 g/mol = 15.17 g KNO₃

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