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larisa86 [58]
3 years ago
11

What is the potential energy of a 2 kg plant that is on a windowsill 1.3 m high

Chemistry
2 answers:
gulaghasi [49]3 years ago
8 0

Answer:

P.E = 25.48 J

Explanation:

Given data:

Mass = 2 Kg

Height = 1.3 m

Potential energy = ?

Solution:

Formula:

P.E = m . g . h

P. E = potential energy

m = mass in kilogram

g = acceleration due to gravity

h = height

Now we will put the values in formula.

P.E = m . g . h

P.E = 2 Kg . 9.8 m /s² . 1.3 m

P.E = 25.48 Kg. m² / s²

 Kg. m² / s² = J

P.E = 25.48 J

Yanka [14]3 years ago
6 0

Answer:i farted

Explanation:

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Harvey kept a balloon with a volume of 348 milliliters at 25.0˚C inside a freezer for a night. When he took it out, its new volu
ad-work [718]

Initial volume of the balloon = V_{1}= 348 mL

Initial temperature of the balloon T_{1} = 25.0^{0}C + 273 = 298 K

Final volume of the balloon V_{2} = 322 mL

Final temperature of the balloon = T_{2} = ?

According to Charles law, volume of an ideal gas is directly proportional to the temperature at constant pressure.

\frac{V_{1} }{T_{1} } =\frac{V_{2} }{T_{2} }

On plugging in the values,

\frac{348mL}{298 K} =\frac{322 mL}{T_{2} }

T_{2} =276 K

Therefore, the temperature of the freezer is 276 K

5 0
3 years ago
Consider the reaction.
N76 [4]

Answer: m = 50 g ZnSO4

Explanation: First is convert the moles of Zn to the moles of ZnSO4 by having their mole ratio which is 2:2 based from the balanced equation. Next is convert the moles of ZnSO4 to mass using its molar mass.

0.311 mole Zn x 2 moles ZnSO4 / 2 moles Zn

= 0.311 moles ZnSO4

0.311 moles ZnSO4 x 161 g ZnSO4 / 1 mole ZnSO4

= 50 ZnSO4

5 0
3 years ago
Read 2 more answers
Duncan takes a break from studying and goes to the gym to swim laps If swimming burns amount of time ? 85 * 10 ^ 5 cal per hour
Volgvan

When 6.85×10⁵ cal is converted to kilojoules, the result obtained is 2866.04 KJ

<h3>Data obtained from the question </h3>
  • Energy (cal) = 6.85×10⁵ cal
  • Energy (KJ) =?

<h3>Conversion scale </h3>

1 cal = 0.004184 KJ

<h3>How to convert 6.85×10⁵ cal to kilojoules</h3>

1 cal = 0.004184 KJ

Therefore,

6.85×10⁵ cal = 6.85×10⁵ × 0.004184

6.85×10⁵ cal = 2866.04 KJ

Thus, 6.85×10⁵ cal is equivalent to 2866.04 KJ

Learn more about conversion:

brainly.com/question/2139943

6 0
2 years ago
Which environment would you most likely have rich fertile soil
eimsori [14]
The environment where rich,fertile soil would most likely be is a flood plain.

Hope this helps!
Can u plz mark me as brainliest? I really need it!
7 0
3 years ago
Un medicamento corresponde a una disolución de "nafazolina" (sustancia activa) en agua purificada, en una concentración de 12% V
ratelena [41]

Answer:

12 mL

Explanation:

Según la pregunta;

V / V% concentración del fármaco = 12%

volumen de la solución = 100 ml

De;

V / V% = volumen de fármaco / volumen de solución

volumen de fármaco = V / V% × volumen de solución

volumen de fármaco = 12/100 × 100

= 12 mL

5 0
3 years ago
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