Answer: 824.6 g of NaCl are produced from 500.0 g of chlorine.
Explanation:
To calculate the moles :
According to stoichiometry :
1 mole of
produce = 2 moles of
Thus 7.04 moles of
will produce=
of
Mass of
Thus 824.6 g of NaCl are produced from 500.0 g of chlorine.
Answer:
The density of the nugget is 19.3g/cm³
It is gold because all samples of gold will have the same density value
You should buy it.
Explanation:
Given parameters:
Density of gold = 19.3g/cm³
Length on all sides = 5cm
Mass in kg = 2.413kg
Unknown:
Density = ?
Is it gold = ?
Should you buy it = ?
Solution:
To solve this problem, we need to find the density of the nugget first.
Density =
Mass = 2.413kg
We need to convert to g:
1kg = 1000g
2.413kg = 2413g
Volume = L³ = 5³ = 125cm³
Therefore;
Density =
= 19.3g/cm³
The density of the nugget is 19.3g/cm³
It is gold because all samples of gold will have the same density value
You should buy it.
Answer: c. Sugar turning black when it burns.
Explanation:
Chemical change is defined as a change in which rearrangement of atoms take place and leads to formation of new substances.
Physical change is defined as a change which leads to change in shape, size or state of the substance changes. No new substance is formed.
a) Water bubbling when it starts to boil is a physical change as it accompanies only a change in phase.
b) Detergent removing grease from a dish is a physical change as no new substance is formed.
c) Sugar turning black when it burns is a chemical change as there occurs a chemical reaction between sugar and oxygen. The oxygen in the air reacts with the sugar and the chemical bonds are broken.
d) Oil and vinegar separating in salad dressing is not a chemical change. It occurs because of difference in densities.
Answer:
molar volume of vapor ethanol is ![V = 1.043 \times 10^{-3} m^3/mol](https://tex.z-dn.net/?f=V%20%3D%201.043%20%5Ctimes%2010%5E%7B-3%7D%20m%5E3%2Fmol)
mass of ethanol is 15430.22 g
Explanation:
By using ideal gas equation
PV = nRT
Where P is pressure , R is gas constant
so, volume is
![V = \frac{RT}{P} = \frac{8.314\times (480+273)}{6000\times 10^3}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7BRT%7D%7BP%7D%20%3D%20%5Cfrac%7B8.314%5Ctimes%20%28480%2B273%29%7D%7B6000%5Ctimes%2010%5E3%7D)
![V = 1.043 \times 10^{-3} m^3/mol](https://tex.z-dn.net/?f=V%20%3D%201.043%20%5Ctimes%2010%5E%7B-3%7D%20m%5E3%2Fmol)
molar volume of vapor ethanol is
![V = 1.043 \times 10^{-3} m^3/mol](https://tex.z-dn.net/?f=V%20%3D%201.043%20%5Ctimes%2010%5E%7B-3%7D%20m%5E3%2Fmol)
b)
volume of vessel is given ![0.35 m^3](https://tex.z-dn.net/?f=0.35%20m%5E3)
therefore total moles of ethanol in given vessel will be
![n =\frac{V_{vessel}}{V}](https://tex.z-dn.net/?f=n%20%3D%5Cfrac%7BV_%7Bvessel%7D%7D%7BV%7D)
![n =\frac{0.35}{1.043\times10^{-3}}](https://tex.z-dn.net/?f=n%20%3D%5Cfrac%7B0.35%7D%7B1.043%5Ctimes10%5E%7B-3%7D%7D)
n = 335.44 mol
we know that
mole is given as [/tex]n = \frac{mass}{moleculae weight}[/tex]
weight of ethanol is 46 g/mol
n\times 46 = mass
![335.44\times 46 = 15430.22 g](https://tex.z-dn.net/?f=335.44%5Ctimes%2046%20%3D%2015430.22%20g)
mass of ethanol is 15430.22 g