Question

Please help me with this question!!

Answer 1

Answer: 824.6 g of NaCl are produced from 500.0 g of chlorine.

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$  $\text{Moles of} Cl_2=\frac{500.00g}{71g/mol}=7.04moles$

$2Na+Cl_2\rightarrow 2NaCl$  

According to stoichiometry :

1 mole of $Cl_2$ produce = 2 moles of $NaCl$

Thus 7.04 moles of $Cl_2$ will produce=$\frac{2}{1}\times 7.04=14.08moles$  of $NaCl$

Mass of $NaCl=moles\times {\text {Molar mass}}=14.08moles\times 58.5g/mol=824.26g$

Thus 824.6 g of NaCl are produced from 500.0 g of chlorine.