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Darina [25.2K]
3 years ago
7

Please help me with this question!!

Chemistry
1 answer:
mestny [16]3 years ago
3 0

Answer: 824.6 g of NaCl are produced from 500.0 g of chlorine.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}  \text{Moles of} Cl_2=\frac{500.00g}{71g/mol}=7.04moles

2Na+Cl_2\rightarrow 2NaCl  

According to stoichiometry :

1 mole of Cl_2 produce = 2 moles of NaCl

Thus 7.04 moles of Cl_2 will produce=\frac{2}{1}\times 7.04=14.08moles  of NaCl

Mass of NaCl=moles\times {\text {Molar mass}}=14.08moles\times 58.5g/mol=824.26g

Thus 824.6 g of NaCl are produced from 500.0 g of chlorine.

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= 1.407                       = 0.7056               = 2.816       (to 4 significant figures)

the smallest number here is 0.7056 so:

1.407÷0.7056        0.7056÷0.7056       2.816÷0.7056

=1.99 approx.2                   = 1                   3.99 approx. 4

here there is no need to carry out step 3 as ratio obtained is already a simplest whole number  ratio

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