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nignag [31]
3 years ago
10

Which statements are true about the rainforest climate? (Select all that apply.)

Chemistry
2 answers:
valentinak56 [21]3 years ago
8 0

Answer:Answer:They have high temperatures and They receive a lot of precipitation.

Explanation:

Alexxandr [17]3 years ago
7 0

Answer:

<em>They have high temperatures </em><em>and </em><em>They receive a lot of precipitation.</em>

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What happens if a species is unable to adapt to a changing environment.
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The awnser your looking for would be B: It's Population decreases. Because if a species is unable to adapt to a changing environment the species would either have to move away or they could die in that location.


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Is a push or a pull.<br><br><br> A.FORCE<br> B.MASS <br><br> ???
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A.Force because your adding pressure to what you are pushing or pulling.
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Which of the following statements is TRUE about the loose rocks on the surface
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Answer:B

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The name of an alkyl group that contains THREE carbon atoms is____
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The answer is "Propyl"

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4 years ago
When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin
loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point

K_f = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality =\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9

8.2^0C=1\times K_f\times 1.9

K_f=4.32^0C/m

Now Depression in freezing point for sodium chloride is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=20.0^0C = Depression in freezing point

K_f = freezing point constant  

m= molality = \frac{136g\times 1000}{950g\times 58.5g/mol}=2.45

20.0^0C=i\times 4.32^0C\times 2.45

i=1.9

Thus vant hoff factor for sodium chloride in X is 1.9

3 0
3 years ago
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