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Ber [7]
3 years ago
10

The gases in the can of compressed air are at the temperature of 298.3 K and a pressure of 270.3. If the gases in the can reach

a pressure of 874.6 the can will explode. What temperature (in K) would the can need to be heated up for it to explode.
Chemistry
2 answers:
Setler79 [48]3 years ago
7 0

Answer:

The gases in the can of compressed air are at the temperature of 298.3 K and a pressure of 270.3.

Explanation:

zimovet [89]3 years ago
4 0

Answer:

The gases in the can of compressed air are at the temperature of 298.3 K and a pressure of 270.3.

Explanation:

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The conductivity of 0.1 mole of NaCl dissolved in 1000 mL of water will be greatest as the number of ions in 0.1 mole of NaCl will be more than 0.001, 0.05 and 0.005 moles of NaCl. Greater the number of ions in the solution, greater will be the conductivity. Specific Conductivity decreases with a decrease in concentration. Since the number of ions per unit volume that carry current in a solution decrease on dilution. Hence, concentration and conductivity are directly proportional to each other.

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3 years ago
3. If you start with 8x1025 molecules of Cl, and 25 grams of KI, how many grams of KCl would
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Answer:

Percent yield = 89.1%

Explanation:

Based on the equation:

Cl₂ + 2KI → 2KCl + I₂

<em>1 mole of Cl₂ reacts with 2 moles of KI to produce to moles of KCl</em>

<em />

To solve this quesiton we must find the moles of each reactant in order to find the limiting reactant. With the limiting reactant we can find the moles of KCl and the mass:

<em>Moles Cl₂:</em>

8x10²⁵ molecules * (1mol / 6.022x10²³ molecules) = 133 moles

<em>Moles KI -Molar mass: 166.0028g/mol-</em>

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Here, clarely, the KI is the limiting reactant

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0.15 moles * (74.5513g / mol) =

11.2g KCl

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<h3>Percent yield = 89.1%</h3>
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