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Zinaida [17]
3 years ago
8

34.74 ÷ 1.2Solve without using a calculator :)​

Mathematics
2 answers:
Citrus2011 [14]3 years ago
6 0

Answer:

28.95

Step-by-step explanation:

tia_tia [17]3 years ago
5 0

Answer:

28.95

Step-by-step explanation:

this stuff is easy

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PLEASE HELP!
kirza4 [7]
Equations with absolute value:

|f(x)| = k

Where k is a positive number; if k is a negative number, the equation is impossible (absolute value is always positive).

How to solve:

|f(x) | = k
- f(x) = k \: \: or \: \: f(x) = k

Then:
1. |x+7|=12
x+7=12 V -x-7=12
x=5 V -x=19
x=5 V x=-19
{-19, 5}

2. |2x+4|=8
2x+4=8 V -2x-4=8
2x=4 V -2x=12
x=2 V x=-6

3. 3|3k|=27
3×3k=27 V 3×(-3k)=27
9k=27 V -9k=27
k=3 V k=-3
{-3, 3}

4. 5|b+8|=30
5×(b+8)=30 V 5×(-b-8)=30
5b+40=30 V -5b-40=30
5b=-10 V -5b=70
b=-2 V b=-14
{-14, -2}

5. |m+9|=5
m+9=5 V -m-9=5
m+9=5 V m+9=-5
4 0
3 years ago
Read 2 more answers
Jeremiah opened a savings account with a one-time deposit of $500. His savings account will pay a 5% simple interest per year. H
jolli1 [7]

Answer:

Jeremiah

Step-by-step explanation:

3 0
2 years ago
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Suppose a tank contains 400 gallons of salt water. If pure water flows into the tank at the rate of 7 gallons per minute and the
Strike441 [17]

Answer:

Step-by-step explanation:

This is a differential equation problem most easily solved with an exponential decay equation of the form

y=Ce^{kt}. We know that the initial amount of salt in the tank is 28 pounds, so

C = 28. Now we just need to find k.

The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is \frac{dy}{dt}. Thus, the change in the concentration of salt is found in

\frac{dy}{dt}= inflow of salt - outflow of salt

Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

3(\frac{y}{400})

Therefore,

\frac{dy}{dt}=0-3(\frac{y}{400}) or just

\frac{dy}{dt}=-\frac{3y}{400} and in terms of time,

-\frac{3t}{400}

Thus, our equation is

y=28e^{-\frac{3t}{400} and filling in 16 for the number of minutes in t:

y = 24.834 pounds of salt

6 0
2 years ago
ILL MARK BRAINLIEST !!!
OLEGan [10]

Answer:

BCF is the correct answer

8 0
3 years ago
Read 2 more answers
In the diagram, the radius of the outer circle is 2x cm and
hodyreva [135]

Area shaded = Area big circle- Area of small circle;

200 pi= pi•(2x)^2 -pi•6^2;

200pi= pi•4x^2 -pi•36;

200pi=pi•4(x^2 -9) divide both sides by 4pi;

50=x^2 -9; So x=sqrt(59)~7.68cm

8 0
3 years ago
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