The pressure difference across the sensor housing will be "95 kPa".
According to the question, the values are:
Altitude,
Speed,
Pressure,
The temperature will be:
→ ![T = 15.04-[0.00649(9874)]](https://tex.z-dn.net/?f=T%20%3D%2015.04-%5B0.00649%289874%29%5D)
→ 
→ 
now,
→ ![P_o = 101.29[\frac{(-49.042+273.1)}{288.08} ]^{(5.256)}](https://tex.z-dn.net/?f=P_o%20%3D%20101.29%5B%5Cfrac%7B%28-49.042%2B273.1%29%7D%7B288.08%7D%20%5D%5E%7B%285.256%29%7D)
→
hence,
→ The pressure differential will be:
= 
= 
Thus the above solution is correct.
Learn more about pressure difference here:
brainly.com/question/15732832
The system includes a disk rotating on a frictionless axle and a bit of clay transferring towards it, as proven withinside the determine above.
<h3>What is the
angular momentum?</h3>
The angular momentum of the device earlier than and after the clay sticks can be the same.
Conservation of angular momentum the precept of conservation of angular momentum states that the whole angular momentum is usually conserved.
- Li = Lf where;
- li is the preliminary second of inertia
- If is the very last second of inertia
- wi is the preliminary angular velocity
- wf is the very last angular velocity
- Li is the preliminary angular momentum
- Lf is the very last angular momentum
Thus, the angular momentum of the device earlier than and after the clay sticks can be the same.
Read more about the frictionless :
brainly.com/question/13539944
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Answer:
The rate of energy absorbed per unit time is 3500W.
Explanation:
From the question, we were given the following parameters;
Plane, opaque, gray, diffuse surface
â = 0.7
Surface area, A = 0.5m²
Incoming radiant energy, G = 10000w/m²
T = 500°C
Rate of energy absorbed is âAG;
âAG = 0.7 × 0.5 × 10000
âAG = 3500W.
The energy absorbed is measured in watts and denoted by the symbol W.
Answer:

Explanation:
Given that
L= 50 m
Pressure drop = 130 KPa
For Copper tube is 3/4 standard type K drawn tube
Outside diameter=22.22 mm
Inside diameter=18.92 mm
Dynamic viscosity for kerosene

Pressure difference given as

Where
L is length of tube
μ is dynamic viscosity
Q is volume flow rate
d is inner diameter of tube
ΔP is pressure drop
Now by putting the values



So flow rate is 