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dem82 [27]
3 years ago
13

If gain of the critically damped system is increased, the system will behave as a) Under damped b) Over damped c) Critically dam

ped d) Oscillatory
Engineering
1 answer:
Ganezh [65]3 years ago
7 0

Answer:

a) Under damped

Explanation:

Given that system is critically damped .And we have to find out the condition when gain is increased.

As we know that damping ratio given as follows

\zeta =\dfrac{C}{C_c}

Where C is the damping coefficient and Cc is the critical damping coefficient.

C_c=2\sqrt{mK}

So from above we can say that

\zeta =\dfrac{C}{2\sqrt{mK}}

\zeta \alpha \dfrac{1}{\sqrt K}

From above relationship we can say when gain (K) is increases then system will become under damped system.

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Answer:

Explanation:

val db = ("John", "x3456", 50.1) :: ("Jane", "x1234", 107.3) ::

        ("Joan", "unlisted", 12.7) :: Nil

 

type listOfTuples = List[(String, String, Double)]

def find_salary(name: String) = {

 def search(t: listOfTuples): Double = t match {

   case (name_, _, salary) :: t if name == name_ => salary

   case _ :: t => search(t)

   case Nil    =>

     throw new Exception("Invalid Argument in find_salary")

 }

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}

def select(pred: (String, String, Double) => Boolean) = {

 def search(found: listOfTuples): listOfTuples = found match {

   case (p1, p2, p3) :: t if pred(p1, p2, p3)  => (p1, p2, p3) :: search(t)

   case (p1, p2, p3) :: t if !pred(p1, p2, p3) => search(t)

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println("Searching the salary of 'Joan' at db: " + find_salary("Joan"))

println("")

 

val predicate = (_:String, _:String, salary:Double) => (salary < 100.0)

println("All employees that match with predicate 'salary < 100.0': ")

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7 0
3 years ago
At a certain location, wind is blowing steadily at 10 m/s. Determine the mechanical energy of air per unit mass and the power ge
ale4655 [162]

Answer:

<em>a) 50 J/kg</em>

<em>b) 721 67 KW</em>

<em></em>

Explanation:

The velocity of the wind v = 10 m/s

diameter of the blades d = 70 m

efficiency of the turbine η = 30%

density of air ρ = 1.25 kg/m^3

The area of the blade A = \pi d^2/4

A = \frac{3.142 * 70^2}{4} = 3848.95 m^2

The mechanical energy air per unit mass is gives as

e = v^2/2 = \frac{10^2}{2} = <em>50 J/kg</em>

<em></em>

Theoretical Power of the turbine P = ρAve

where

ρ is the density of air

A is the area of the blade

v is the velocity of the wind

e is the energy per unit mass

substituting values, we have

P = 1.25 x 3848.95 x 10 x 50 = 2405593.75 W

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where η is the efficiency of the turbine

P is the theoretical power of the turbine

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