Don't be snarky !
<u>4x - x/4 + x + 1/3 = 2x</u>
Add up the 'x' terms on the left side: (4 + 1/4 + 1)x = 5-1/4 x = 21/4 x
Now the equation is: 21/4 x + 1/3 = 2x
2x is the same as 8/4 x . Subtract it from each side:
13/4x + 1/3 = 0
Subtract 1/3 from each side :
13/4 x = - 1/3
Multiply each side by 4 :
13 x = - 4/3
Divide each side by 13 :
<em>x =</em> (- 4/3) / (13) = <em>- 4 / 39</em>
The cube root is 10 bc 10x10x10 = 100
For x > 2, you would circle the 2, but you would not shade it in because it is greater than/ less than, not greater than or equal to/less than or equal to. From there on, you would move it to the right, because here x is greater than 2, and the numbers to the right of 2 are greater than two.
For x < 2, you would again circle the 2, but don't shade it in. And then you would make a line heading towards the left, because the numbers to the left of 2 are smaller than 2, and here, x is smaller than 2, since 2 is greater.
A value that is not the solution to either inequality is 2. 2 is not greater than 2, and 2 is not less than 2.
A pythagoras triplet is a set of three numbers ... not just any three numbers,
but a set where the (square of one of them) is the sum of the (squares of the
other two).
If they're related in that way, then they can be the lengths of the sides of a
right triangle.
If they're not, then they can't.
