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blsea [12.9K]
2 years ago
5

Derive the explicit rule for the pattern 3, 0, -3, -6, -9,

Physics
2 answers:
pickupchik [31]2 years ago
8 0
It is the last number minus 3
bagirrra123 [75]2 years ago
3 0
It’s the number -3 (subtract three)
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In the previous part, you determined the maximum angle that still allows the crate to remain at rest. If the coefficient of fric
lorasvet [3.4K]

Answer:

B. The maximum angle decreases

Explanation:

If θ be the maximum angle of a slope that allows a crate placed on it to remain at rest , following condition exists .

tanθ = μ , θ is called angle of repose . μ is coefficient of static friction .

So the tan of angle of repose θ is proportional to coefficient of static friction.

If coefficient of static friction is less than .7 , naturally angle of repose will also become less ,ie,  it at lower angle of inclination , the object will start slipping .

7 0
3 years ago
An electron with a charge value of 1.6 x 10-19 C is moving in the presence of an electric field of 400 N/C. What force does the
Vsevolod [243]

Answer:

4.0×10⁻¹⁷ N

Explanation:

4 0
2 years ago
Could you please explain to me Newton's second law of motion? Please I don't get it :/
MissTica

Answer:

Newton's second law states that when a body of mass m is accelerated with force f

then F=ma

this means acceleration of an object depends on both force with which it is moving as well as its mass

8 0
3 years ago
A wheel accelerates from rest to 34.7 rad/s at a rate of 47.0 rad/s^2. Through what angle (in radians) did the wheel turn while
dem82 [27]

12.8 rad

Explanation:

The angular displacement \theta through which the wheel turned can be determined from the equation below:

\omega^2 = \omega_0^2 + 2\alpha\theta (1)

where

\omega_0 = 0

\omega = 34.7\:\text{rad/s}

\alpha = 47.0\:\text{rad/s}^2

Using these values, we can solve for \theta from Eqn(1) as follows:

2\alpha\theta = \omega^2 - \omega_0^2

or

\theta = \dfrac{\omega^2 - \omega_0^2}{2\alpha}

\:\:\:\:= \dfrac{(34.7\:\text{rad/s})^2 - 0}{2(47.0\:\text{rad/s}^2)}

\:\:\:\:= 12.8\:\text{rad}

7 0
2 years ago
Find the mass of an object if a 40 N of force causes the object to accelerate at 5.5 m/s/s
Murrr4er [49]

Answer:

<h3>The answer is 8 kg</h3>

Explanation:

The mass of the object can be found by using the formula

m =  \frac{f}{a}  \\

f is the force

a is the acceleration

From the question we have

m =  \frac{40}{5}  \\

We have the final answer as

<h3>8 kg</h3>

Hope this helps you

7 0
3 years ago
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