Answer:
The term rotational and irrotational flow is associated withe the flow of particles in fluid.
The common example of irrrotational flow can be seen on the carriages of the Ferris wheel (giant wheel).
Explanation:
- If the fluid is rotating along its axis with the streamline flow of its particles,then this type of flow is rotational flow.
- Similarly if fluid particles do not rotate along its axis while flowing in a stream line flow then it is considered as the irrotational flow.
- In majority, if the flow of fluid is viscid then it is rotational.
- Fluid in a rotating cylinder is an example of rotating flow.
A mixture is a substance made by mixing other substances together.
Explanation:
It is given that,
Fundamental frequency, f = 220 Hz
(a) We know that at 0 degrees, the speed of sound in air is 331 m/s.
For open pipe, ![\lambda=2l](https://tex.z-dn.net/?f=%5Clambda%3D2l)
l is the length of pipe
Also,
![v=f\lambda](https://tex.z-dn.net/?f=v%3Df%5Clambda)
![l=\dfrac{v}{2f}=\dfrac{331}{2\times 220}=0.75\ m](https://tex.z-dn.net/?f=l%3D%5Cdfrac%7Bv%7D%7B2f%7D%3D%5Cdfrac%7B331%7D%7B2%5Ctimes%20220%7D%3D0.75%5C%20m)
(b) Let f' is the fundamental frequency of the pipe at 30 degrees and v' is its speed.
![v'=331\sqrt{1+\dfrac{T}{273}}](https://tex.z-dn.net/?f=v%27%3D331%5Csqrt%7B1%2B%5Cdfrac%7BT%7D%7B273%7D%7D)
![v'=331\sqrt{1+\dfrac{30}{273}}](https://tex.z-dn.net/?f=v%27%3D331%5Csqrt%7B1%2B%5Cdfrac%7B30%7D%7B273%7D%7D)
v' = 348.71 m/s
So, ![f'=\dfrac{v'}{\lambda}](https://tex.z-dn.net/?f=f%27%3D%5Cdfrac%7Bv%27%7D%7B%5Clambda%7D)
![f'=\dfrac{348.71}{2\times 0.75}](https://tex.z-dn.net/?f=f%27%3D%5Cdfrac%7B348.71%7D%7B2%5Ctimes%200.75%7D)
f' = 232.4 Hz
Hence, this is the required solution.
If you know the distance and the time I travelled that distance.
You just have to divide the time from the distance to get velocity
V =d
_
t
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