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fenix001 [56]
3 years ago
6

Please help quickly! i will mark brainliest

Chemistry
1 answer:
bogdanovich [222]3 years ago
7 0

Answer:

Energy of the Reactant: increases

Energy of the product: not at all

Rate of reaction: increases

Enthalpy: not at all

Activation energy: decreases

Explanation:

Catalyst is a substance that increases the rate of reaction than normal to form a product.

Catalyst affect differently to different factors of reaction. A catalyst is meant to increase rate of reaction by lowering the activation energy, so that collision between reactant increase and that passes the energy barrier to form the product faster.

Catalyst has no effect on Enthalpy as change in enthalpy only depends on the chemical compositions of the reactants and products.

Catalyst also increases energy of reactant so that they can collide faster than before and do not affect the energy of product at all.

Hence, the correct answer is:

Energy of the Reactant: increases

Energy of the product: not at all

Rate of reaction: increases

Enthalpy: not at all

Activation energy: decreases

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Answer:

1120 gm

Explanation:

6. Consider the reaction: CzHo (g) + 02 (8) - 4 CO2(g) + 6H2O (1)

(a) Balance the equation.

(b) How many grams of oxygen are required to react with 10 moles of ethane for a complete

combustion reaction?

FIRST, CORRECT THE EQUATION THEN BALANCE

2C2H6(G) + 7O2------------>  4CO2  + 6H2O

so for 10 moles of ethane, we need

7 X 5 = 35 MOLES O2

=35 MOLES O2

O2 HAS A MOLAR MASS OF 2X16 = 32 gm

35 MOLES OF O2 HAS A MASS OF 35 X 32 =1120 gm

6 0
3 years ago
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Answer:C. The value of n for H+(H2O)n can be calculated for almost all solutions.

Explanation:

An hydrate can be described as a substance that contains water or with an hydrogen bonded water molecule group.

The hydrate group doesn't necessarily have a fixed formula.

5 0
4 years ago
The amount of matter in an object is known as
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4 0
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A certain reaction is exothermic in the forward direction. The reaction has more moles of gas on the product side. Which of the
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4 years ago
Glucose, C 6 H 12 O 6 , is used as an energy source by the human body. The overall reaction in the body is described by the equa
MA_775_DIABLO [31]

Answer:

m_{O_2}=61.87gO_2

m_{CO_2}=85.07gCO_2

Explanation:

Hello,

Considering the given reaction's stoichiometry, grams of oxygen result:

m_{O_2}=58.0gC_6H_{12}O_6*\frac{1molC_6H_{12}O_6}{180gC_6H_{12}O_6}*\frac{6molO_2}{1molC_6H_{12}O_6}*\frac{32gO_2}{1molO_2}\\m_{O_2}=61.87gO_2

Moreover, the mass of produced carbon dioxide turns out:

m_{CO_2}=58.0gC_6H_{12}O_6*\frac{1molC_6H_{12}O_6}{180gC_6H_{12}O_6}*\frac{6molCO_2}{1molC_6H_{12}O_6}*\frac{44gCO_2}{1molCO_2}\\m_{O_2}=85.07gCO_2

Best regards.

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3 years ago
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