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UNO [17]
2 years ago
5

Express your answer using two significant figures. 2.7 cm3 = m3 2.0 mm3= m3

Chemistry
1 answer:
natka813 [3]2 years ago
8 0

Answer:

2.7 cm³ = 2.7 x 10⁻⁶ m³

2.0 mm³ = 2.0 x 10⁻⁹ m³

Explanation:

The values are multiplied by the conversion ratio, being sure to raise the ratio to the power of 3 so that the units properly cancel:

(2.7 cm³)(1m/100cm)³ = 2.7 x 10⁻⁶ m³

(2.0 mm³)(1m/1000mm)³ = 2.0 x 10⁻⁹ m³

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velikii [3]

Answer:

m_{leftover}=37g

Explanation:

Hello!

In this case, since the melting process involves the heat added to the system, the heat of fusion and the mass of water:

Q=m\Delta H_{fus}

Thus, as it has been reported that the heat of fusion of ice is 333.6 J/g, we can compute the melted mass of ice as shown below:

m=\frac{Q}{\Delta H_{fus}} =\frac{46000J}{333.6J/g}\\\\m=138g

Thus, the ice leftover results:

m_{leftover}=175g-138g\\\\m_{leftover}=37g

Regards!

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3 years ago
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Explanation:

5 0
3 years ago
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posledela

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6 0
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What are the spectator ions in the reaction between mg(oh)2 (aq) and hcl (aq)?
vivado [14]

The spectator ions in the reaction between aqueous Mg(OH)_2 and aqueous HCl would be   Mg^{2+ and Cl^- ions.

<h3>What are spectator ions?</h3>

Spectator ions are anions or cations that exist both as reactants and as products in a reaction. Their forms remain unchanged both in the reactants and in the products.

Aqueous Mg(OH)_2 and aqueous HCl  react according to the following equation:

Mg (OH)_2 (aq) + 2HCl (aq) --- > MgCl_2 (aq) +2 H_2O (l)

Before the reaction, Mg^{2+ and Cl^- existed in the reactants as Mg(OH)_2 and HCl respectively. After the reaction,  Mg^{2+ and Cl^- exist as MgCl_2 in the product.

Thus, the spectator ions in this case are  Mg^{2+ and Cl^- ions because their forms did not change after the reaction.

More on spectator ions can be found here: brainly.com/question/28913274

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