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Nookie1986 [14]
3 years ago
15

Concept Simulation 20.4 provides background for this problem and gives you the opportunity to verify your answer graphically. Ho

w many time constants (a decimal number) must elapse before a capacitor in a series RC circuit is charged to 65.0% of its equilibrium charge?
Physics
1 answer:
77julia77 [94]3 years ago
6 0

Answer:

The time constant is 1.049.

Explanation:

Given that,

Charge q{t}= 0.65 q_{0}

We need to calculate the time constant

Using expression for charging in a RC circuit

q(t)=q_{0}[1-e^{-(\dfrac{t}{RC})}]

Where, \dfrac{t}{RC} = time constant

Put the value into the formula

0.65q_{0}=q_{0}[1-e^{-(\dfrac{t}{RC})}]

1-e^{-(\dfrac{t}{RC})}=0.65

e^{-(\dfrac{t}{RC})}=0.35

-\dfrac{t}{RC}=ln (0.35)

-\dfrac{t}{RC}=-1.049

\dfrac{t}{RC}=1.049

Hence, The time constant is 1.049.

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