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3 years ago

What term is given to a substance that can dissolve in a particular liquid?

Physics

2 answers:

Norma-Jean [14]3 years ago

3 0

Answer:

Solute

Explanation:

Something dissolved in a liquid is called a solution. The dissolved substance is called the solute. The liquid used for dissolving is called the solvent.

svlad2 [7]3 years ago

3 0

Answer:

solute

Explanation:

Solubility is a chemical property referring to the ability for a given substance, the solute, to dissolve in a solvent. It is measured in terms of the maximum amount of solute dissolved in a solvent at equilibrium. The resulting solution is called a saturated solution.

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A stone is dropped from a bridge 45 meters above the surface river. It takes the stone 4.6 seconds to reach the water surface. F

Hunter-Best [27]

The most interesting thing about this problem is that in order to use all of the given information, you need to ignore the laws of Physics, and never mind what the stone would really do if dropped from a real bridge in the real world.

Average velocity = (displacement) / (time for the displacement)

Displacement =
Straight path from the start point to the finish point = 45 meters down .
Time = 4.6 seconds

Average velocity = 45/4.6 = <em>9.783 meters/second down</em>

==================================

In the real world, a dropped stone would only take 3.03 seconds
to fall 45 meters.

Alternatively, a stone that fell for 4.6 seconds from rest would fall
103.7 meters, with an average velocity of 22.5 meters/second down.

But we accepted the given information, and did the best we could do
with it.

7 0

3 years ago

Read 2 more answers

A car traveling 75 km/h slows down at a constant 0.50 m/s2 just by "letting up on the gas." calculate (a) the distance the car c

Serjik [45]

Solution:

At 1st convert km/h to m/s. 1 km = 1000 m, 1 h = 3600 s, 1 km/m = 1000/3600 = 5/18 m/s

Initial velocity = 75 * 5/18 = 20.8 m/s

The car’s velocity decreases from 20.8 m/s to 0 m/s at the rate of 0.5 m/s each second. We have the final velocity, initial velocity, and the acceleration.

Now according to the equation determine the distance.

vf^2 = vi^2 + 2 * a * d

a = -0.5 m/s^2

0 = 20.8^2 + 2 * -0.5 * d

so d = 431.64 m

since we have the final velocity, initial velocity, and the acceleration. Use the following equation to determine time.

vf = vi + a * t

0 = 20.8 – 0.5 * t

Solve for t = 41 seconds

d = vi * t + ½ * a * t^2

d1 = 20.8 * 1 – ½ * 0.5 * 1^2 = 20.55 m

The easiest way to the distance for the 5th second is:

d = vi * t + ½ * a * t^2, a = -0.5

d5 = 20.8 * 5 – ½ * 0.5 * 5^2 = 91.5 m

d6 = 20.8 * 6 – ½ * 0.5 * 6^2 = 106.8m

d6 – d5 = 15.3 m

this is the required solution.

3 0

3 years ago

What is the difference between a muscular strength exercise and a muscular endurance exercise?

joja [24]

Answer:

What is the difference between muscular strength and muscular endurance? Muscular strength is a measure of how much force you can exert in one repetition. Muscular endurance refers to the ability to perform a specific muscular action for a prolonged period of time.

Explanation:

6 0

3 years ago

If the San Andreas Fault moves 200 cm (2 meters) per big earthquake, and plate movement is xx cm/yr (see question above), how ma

weqwewe [10]

Answer:

Option C

80 years

Explanation:

<em>From Scientific records, the rate of movement of the plate is 0.025 meters</em>

Since the fault moves at the rate of 2 meters per year, to obtain the number of years it will takes to produce an earth quake, we will have to divide the rate of movement of the fault by the rate of movement of the plate.

Number of years for earthquake = $\frac{2}{0.025}$ = 80 years.

Hence, it will take 80 years to produce one big earthquake.

5 0

4 years ago

05. The time required to complete one lap around a perfectly circular track having a radius of 1,835 meters is 86

likoan [24]

Answer:

v = 134.06 m/s

Explanation:

Given that,

Radius of a circular track is 1,835 m

Time required to complete one lap around a perfectly circular track is 86 seconds

We need to find the car's velocity. Velocity is equal to,

v=d/t

On circular path,

$v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 1835}{86}\\\\v=134.06\ m/s$

So, car's velocity is 134.06 m/s.

7 0

4 years ago