Answer:
If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases. If the distance is doubled, the force of gravity is one-fourth as strong as before.
Answer:
0.25
Explanation:
Magnification = image distance/object distance
mag = v/u.................. Equation 1
Given: f = -10 cm ( diverging lens) u = 30 cm.
Where can calculate for the value of v using
1/f = 1/u+1/v
make v the subject of the equation
v = fv/(u-f)..................... Equation 2
Substitute into equation 2
v = -30(10)/(30+10)
v = -300/40
v = -7.5 cm.
substituting into equation 1,
mag = 7.5/30
mag = 0.25
hence the magnification of the wretch = 0.25
Answer:
5N
Explanation:
Given parameters:
Original length = 22cm
Spring constant, K = 50N/m
New length = 32cm
Unknown
Force applied = ?
Solution:
The force applied on a spring can be derived using the expression below;
Force = KE
k is the spring constant
E is the extension
extension = new length - original length
extension = 32cm - 22cm = 10cm
convert the extension from cm to m;
100cm = 1m;
10cm will give 0.1m
So;
Force = 50N/m x 0.1m = 5N
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Answer:
Create a table to record the data
Explanation:
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