Weight is the measurement of the pull of gravity on an object, while mass is the measurement of the amount of matter that an object contains.
Answer:
5.63
Explanation:
Divide mass by volume, which will give you 5.63. For instance, 45 divide by 8 what is it? find out
Answer:
Part 1)
![\tau_1 = 5 \times (0.50) = 2.5 N m](https://tex.z-dn.net/?f=%5Ctau_1%20%3D%205%20%5Ctimes%20%280.50%29%20%3D%202.5%20N%20m)
Part 2)
![\tau_2 = 14 \times (0.30) = 4.2 N m](https://tex.z-dn.net/?f=%5Ctau_2%20%3D%2014%20%5Ctimes%20%280.30%29%20%3D%204.2%20N%20m)
Part 3)
![\tau_3 = 1.4 N m](https://tex.z-dn.net/?f=%5Ctau_3%20%3D%201.4%20N%20m)
Part 4)
Since torque on right side is more so here it will turn and slip over it
Explanation:
As we know that the block A is placed at distance
d = 50 cm from the hinge at 70 cm mark
So torque due to weight of A is given as
![\tau_1 = 5 \times (0.50) = 2.5 N m](https://tex.z-dn.net/?f=%5Ctau_1%20%3D%205%20%5Ctimes%20%280.50%29%20%3D%202.5%20N%20m)
the block B is placed at distance
d = 30 cm from the hinge at 70 cm mark
So torque due to weight of B is given as
![\tau_2 = 14 \times (0.30) = 4.2 N m](https://tex.z-dn.net/?f=%5Ctau_2%20%3D%2014%20%5Ctimes%20%280.30%29%20%3D%204.2%20N%20m)
Now torque due to weight of the scale is given as
![\tau_3 = 7(0.20)](https://tex.z-dn.net/?f=%5Ctau_3%20%3D%207%280.20%29)
![\tau_3 = 1.4 N m](https://tex.z-dn.net/?f=%5Ctau_3%20%3D%201.4%20N%20m)
now torque on left side of scale is given as
![\tau_{left} = \tau_1 + \tau_3](https://tex.z-dn.net/?f=%5Ctau_%7Bleft%7D%20%3D%20%5Ctau_1%20%2B%20%5Ctau_3)
![\tau_{left} = 2.5 + 1.4 = 3.9 N m](https://tex.z-dn.net/?f=%5Ctau_%7Bleft%7D%20%3D%202.5%20%2B%201.4%20%3D%203.9%20N%20m)
Torque on right Side is given as
![\tau_{right} = \tau_2 = 4.2 Nm](https://tex.z-dn.net/?f=%5Ctau_%7Bright%7D%20%3D%20%5Ctau_2%20%3D%204.2%20Nm)
Since torque on right side is more so here it will turn and slip over it
Answer:Because if the shape gets changed it will move faster without to much weight
Explanation:
Answer:
8 N North.
Explanation:
Given that,
One force has a magnitude of 10 N directed north, and the other force has a magnitude of 2 N directed south.
We need to find the magnitude of net force acting on the object.
Let North is positive and South is negative.
Net force,
F = 10 N +(-2 N)
= 8 N
So, the magnitude of net force on the object is 8 N and it is in North direction (as it is positive). Hence, the correct option is (d) "8N north".