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swat32
4 years ago
11

The atomic mass of an atom of carbon is 12 amu, and the atomic mass of an atom of oxygen is 16 amu. To produce CO2, 16 g of oxyg

en combine with 12 g of carbon. To produce CO2, 32 g of oxygen combine with 12 g of carbon. The ratio of the mass of oxygen in CO2 to the mass of oxygen in CO is A 8:3. B 1:1. C 2:1. D 1:2.
Chemistry
1 answer:
antiseptic1488 [7]4 years ago
4 0

Answer : The correct option is, (C) 2 : 1

Explanation : Given,

Atomic mass of carbon = 12 amu

Atomic mass of oxygen = 16 amu

To produce CO, 16 g of oxygen combine with 12 g of carbon. That means,

Mass of oxygen in CO = 16 g

Mass of carbon in CO = 12 g

To produce CO_2, 32 g of oxygen combine with 12 g of carbon. That means,

Mass of oxygen in CO_2 = 32 g

Mass of carbon in CO_2 = 12 g

Now we have to determine the ratio of the mass of oxygen in CO_2 to the mass of oxygen in CO.

\frac{\text{Mass of O in }CO_2}{\text{Mass of O in }CO}=\frac{32g}{16g}

\frac{\text{Mass of O in }CO_2}{\text{Mass of O in }CO}=\frac{2}{1}

Therefore, the ratio of the mass of oxygen in CO_2 to the mass of oxygen in CO is, 2 : 1

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Answer:

undergo death as result of the water loss from cell

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3 years ago
Which layer contains almost 90% of the atmosphere's total mass?
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The answer is the troposphere

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I’ve missed this question twice now. Please help
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Explanation:

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3 years ago
Plz help i need the answer ASAP If 6.20 cm3 of a 6.75 M (M = mol/dm3) solution are diluted to 85.6 cm3 with water, what is the c
Brilliant_brown [7]

Answer:

Option A. 6.75 (6.20/85.6)

Explanation:

The following data were obtained from the question:

Initial volume (V1) = 6.2cm³

Initial concentration (C1) = 6.75M

Final volume (V2) = 85.6cm³

Final concentration (C2) =.?

The final concentration can be obtained by using the dilution formula as show below:

C1V1 = C2V2

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Divide both side by 85.6

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6 0
3 years ago
What is the boiling point of a solution of 76 g of water dissolved in 500 mL of acetic acid, CH3COOH?
tatuchka [14]

Answer:

127.3° C, (This is not a choice)

Explanation:

This is about the colligative property of boiling point.

ΔT = Kb . m . i

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Kb = Boiling constant

m = molal (mol/kg)

i = Van't Hoff factor (number of particles dissolved in solution)

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T° boling of solution - 118.1°C =  0.52°C . m . 2

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Mol of water are mass / molar mass

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These moles are in 476.6 g

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T° boling of solution =  0.52°C . 8.85 m . 2 + 118.1°C =  127.3°C

6 0
3 years ago
Read 2 more answers
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