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nordsb [41]
3 years ago
15

Nitrogen gas (N2) and hydrogen gas (H2) combine to form ammonia (NH3).

Chemistry
2 answers:
poizon [28]3 years ago
4 0
Answer 4.
N2 + 3H2 ---> 2NH3
masya89 [10]3 years ago
3 0

Answer: Option (d) is the correct answer.

Explanation:

When nitrogen gas chemically reacts with hydrogen gas then it results in the formation of ammonia gas.

The chemical reaction equation for this will be as follows.

           N_{2} + H_{2} \rightarrow NH_{3}

To balance this equation, we need to a multiply H_{2} by 3 on reactant side, And, we also need to multiply NH_{3} by 2.

Therefore, the equation which will correctly represent this reaction will be as follows.

             N_{2} + 3H_{2} \rightarrow 2NH_{3}      

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C5H6 reacts with itself to form C10H12 according to the following process
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4 0
3 years ago
Propane burns in oxygen to produce carbon dioxide and water what is the percent yeild
amid [387]

Answer:

The percentage yield is 78.2g

Explanation:

Given, mass of propane = 42.8 g , sufficient O2 percent yield = 61.0 % yield.

Reaction - C3H8(g)+5O2(g)------> 3CO2(g)+4H2O(g)

First we need to calculate the moles of propane

Moles of propane = \frac{42.8}{44.096} g.mol-1

                            = 0.971 moles

So, moles of CO2 from the moles of propane

1 mole of C3H8(g) = 3 moles of CO2(g)

So, 0.971 moles of C3H8(g) = ?

= 2.913 moles of CO2

So theoretical yield = 2.913 moles \times 44.0 g/mol

                               = 128.2 g

So, the actual mass of CO2 = percent yield \times  theoretical yield / 100 %

                                         = 61.0 % \times  128.2 g / 100 %

                                         = 78.2 g

the mass of CO2 that can be produced if the reaction of 42.8 g of propane and sufficient oxygen has a 61.0 % yield is 78.2 g

4 0
3 years ago
What is the % yield when 140.0 grams of Ethylene gas (C2H4) reacts with excess chlorine to form 280.0 grams of 1,2-Dichloro Etha
Arlecino [84]

Answer:

The % yield is 56.6 %

Explanation:

This is the reaction:

C₂H₄ + Cl₂  →  C₂H₄Cl₂

Molar mass of ethylene gas: 28 g/m

Mol = mass / molar mass

140 g / 28 g/m = 5 moles

Ratio is 1:1, so 5 moles of ethylene produce 5 moles of dichloro ethane.

Molar mass of C₂H₄Cl₂ = 98.9 g/m

Mass of C₂H₄Cl₂ produced = 98.9 g/m . 5 m → 494.5 g

% yield reaction

(280 g / 494.5 g ) . 100 = 56.6%

6 0
4 years ago
Read 2 more answers
What is the energy of a photon of violet light with a frequency of 7.57x10^14 s^-1?
Eddi Din [679]

Answer:

ΔE = 5.02 x 10⁻¹⁹ j

Explanation:

ΔE (photon) = h·f = (6.63 x 10⁻³⁴ j·s)(7.57 x 10¹⁴ s⁻¹) = 5.02 x 10⁻¹⁹ j

h = Planck's Constant = 6.63 x 10⁻³⁴ j·s

f = frequency (given) = 7.57 x 10¹⁴ s⁻¹

6 0
3 years ago
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