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marta [7]
3 years ago
6

How many grams of K2O will be produced from 0.50 g of K and 0.10 g of O2?

Chemistry
1 answer:
Rudik [331]3 years ago
7 0

Answer:

0.6g

Explanation:

Given parameters:

Mass of K = 0.5g

Mass of O₂  = 0.10g

Unknown:

Mass of K₂O  = ?

Solution:

To solve this problem, let us write the reaction equation first;

                   4K   +   O₂     →     2K₂O

The reaction above delineates the balanced chemical reaction.

To solve this problem, we need to know the limiting reactant. This reactant is the one that determines the amount and extent of the reaction because it is given in short supply. The other reactant is the one in excess.

Start off by find the number of moles of the reactant;

     Number of moles =  \frac{mass}{molar mass}

         Molar mas of K  = 39g/mol

          Molar mass of O₂   = 2(16) = 32g/mol

 Number of moles of K  = \frac{0.5}{39}   = 0.013moles

 Number of moles of O₂    = \frac{0.1}{32}   = 0.031moles

From the balanced reaction;

          4 moles of K reacted with 1 mole of O₂

         0.013 moles of K will react with \frac{0.013}{4}   = 0.0078 moles of O₂

We see that oxygen gas is in excess. We were given 0.031moles of the gas but only require 0.0078moles of oxygen gas.

The limiting reactant is potassium.

    therefore;

              4 moles of K produced 2 moles of K₂O

             0.013 moles of K will produce \frac{0.013 x 2}{4}   = 0.0065‬moles of K₂O

to find the mass of K₂O;

   Mass of K₂O  = number of moles x molar mass

                Molar mass of K₂O  = 2(39) + 16  = 94g/mol

  Mass of K₂O = 0.0065 x 94  = 0.6g

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7 0
3 years ago
What is the percent of hydrogen by mass in CH4O?<br> (H:1.00 amu, C: 12.01 amu, O: 16.00 amu)
cricket20 [7]

The mass percent of hydrogen in CH₄O is 12.5%.

<h3>What is the mass percent?</h3>

Mass percent is the mass of the element divided by the mass of the compound or solute.

  • Step 1: Calculate the mass of the compound.

mCH₄O = 1 mC + 4 mH + 1 mO = 1 (12.01 amu) + 4 (1.00 amu) + 1 (16.00 amu) = 32.01 amu

  • Step 2: Calculate the mass of hydrogen in the compound.

mH in mCH₄O = 4 mH = 4 (1.00 amu) = 4.00 amu

  • Step 3: Calculate the mass percent of hydrogen in the compound.

%H = (mH in mCH₄O / mCH₄O) × 100%

%H = 4.00 amu / 32.01 amu × 100% = 12.5%

The mass percent of hydrogen in CH₄O is 12.5%.

Learn more about mass percent here:brainly.com/question/4336659

3 0
2 years ago
The table below compares the radioactive decay rates of two materials. Material Original mass of material (in grams) Mass of mat
Dmitry [639]

Answer:

The half-life of Material 1 and Material 2 are equal.

step by step explanation;

Material 1 disintegrates to half its mass three times in 21.6 s, to go from 100g

to 12.5g. That is,

100g - 50g - 25g - 12.5g

Material 2 disintegrates to half its mass three times in 21.6 s, to go from 200g to 25g. That is,

200g - 50g - 25g - 12.5g.

This means that regardless of their initial masses involved, material 1 and material 2 have equal half-life.

Their half-life is 21.6 ÷ 3 = 7.2 sec

8 0
3 years ago
HELPPPP!<br> can we manufacture water? why or why not
Furkat [3]

Answer:

No because water needs to have no salt

Explanation:

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3 years ago
A reaction between liquid reactants takes place at - 11.0 degree C in a sealed, evacuated vessel with a measured volume of 45.0
Sati [7]

Explanation:

The given data is as follows.

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As molar mass of chlorine pentafluoride is 130.445 g/mol. Hence, number of moles of chlorine pentafluoride are as follows.

      No. of moles = \frac{mass}{\text{molar mass}}

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Now, using the ideal gas equation we will find the pressure as follows.

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Thus, we can conclude that pressure of chlorine pentafluoride gas in the given reaction vessel after the reaction is 0.139 atm.

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