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icang [17]
3 years ago
7

Matthew is five feet tall. He is standing next to a flagpole on a sunny day. Matthew's shadow is three feet long. At the same ti

me, the shadow of the flagpole is 15 feet long. How tall is the flagpole? (Express answer in feet and inches.) ANSWER ASAP I NEED IT BY 2 PM (if you show work and it is the right answer i will give you brainliest)
Mathematics
1 answer:
natita [175]3 years ago
7 0

Answer: The pole is 17 feet long

Step-by-step explanation: If Matthew's shadow is 2 feet smaller than his actually size, the shadow of the pole will also be reduced. Since the pole's shadow is 15 feet long, adding 2 will give you its original size, 17 feet.

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X + (-9) = 32<br> What is the answer
bezimeni [28]

Answer:

the answer to x+(-9)=32 is x=41

3 0
3 years ago
Read 2 more answers
A. Do some research and find a city that has experienced population growth.
horrorfan [7]
A. The city we will use is Orlando, Florida, and we are going to examine its population growth from 2000 to 2010. According to the census the population of Orlando was 192,157 in 2000 and 238,300 in 2010. To examine this population growth period, we will use the standard population growth equation N_{t} =N _{0}e^{rt}
where:
N(t) is the population after t years
N_{0} is the initial population 
t is the time in years 
r is the growth rate in decimal form 
e is the Euler's constant 
We now for our investigation that N(t)=238300, N_{0} =192157, and t=10; lets replace those values in our equation to find r:
238300=192157e^{10r}
e^{10r} = \frac{238300}{192157}
ln(e^{10r} )=ln( \frac{238300}{192157} )
r= \frac{ln( \frac{238300}{192157}) }{10}
r=0.022
Now lets multiply r by 100% to obtain our growth rate as a percentage:
(0.022)(100)=2.2%
We just show that Orlando's population has been growing at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

B. Here we will examine the population decline of Detroit, Michigan over a period of ten years: 2000 to 2010.
Population in 2000: 951,307
Population in 2010: 713,777
We know from our investigation that N(t)=713777, N_{0} =951307, and t=10. Just like before, lets replace those values into our equation to find r:
713777=951307e^{10r}
e^{10r} = \frac{713777}{951307}
ln(e^{10r} )=ln( \frac{713777}{951307} )
r= \frac{ln( \frac{713777}{951307}) }{10}
r=-0.029
(-0.029)(100)= -2.9%.
We just show that Detroit's population has been declining at a rate of 2.2% from 2000 to 2010. Its population increased from 192,157 to 238,300 in ten years.

C. Final equation from point A: N(t)=192157e^{0.022t}.
Final equation from point B: N(t)=951307e^{-0.029t}
Similarities: Both have an initial population and use the same Euler's constant.
Differences: In the equation from point A the exponent is positive, which means that the function is growing; whereas, in equation from point B the exponent is negative, which means that the functions is decaying.

D. To find the year in which the population of Orlando will exceed the population of Detroit, we are going equate both equations N(t)=192157e^{0.022t} and N(t)=951307e^{-0.029t} and solve for t:
192157e^{0.022t} =951307e^{-0.029t}
\frac{192157e^{0.022t} }{951307e^{-0.029t} } =1
e^{0.051t} = \frac{951307}{192157}
ln(e^{0.051t})=ln( \frac{951307}{192157})
t= \frac{ln( \frac{951307}{192157}) }{0.051}
t=31.36
We can conclude that if Orlando's population keeps growing at the same rate and Detroit's keeps declining at the same rate, after 31.36 years in May of 2031 Orlando's population will surpass Detroit's population.

E. Since we know that the population of Detroit as 2000 is 951307, twice that population will be 2(951307)=1902614. Now we can rewrite our equation as: N(t)=1902614e^{-0.029t}. The last thing we need to do is equate our Orlando's population growth equation with this new one and solve for t:
192157e^{0.022t} =1902614e^{-0.029t}
\frac{192157e^{0.022t} }{1902614e^{-0.029t} } =1
e^{0.051t} = \frac{1902614}{192157}
ln(e^{0.051t} )=ln( \frac{1902614}{192157} )
t= \frac{ln( \frac{1902614}{192157}) }{0.051}
t=44.95
We can conclude that after 45 years in 2045 the population of Orlando will exceed twice the population of Detroit. 

  
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3 years ago
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ArbitrLikvidat [17]
Eduardo is packing 12 pairs of mismatched socks for his trip.
3 0
3 years ago
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the ortiz will travel fron indianapolis to denver this summer.The driving distance between the two cities is 1058 miles. They ne
Sladkaya [172]

Answer:

  a. 2116 miles

  b. 105.8 gallons

  c. $305.76

  d. cost per gallon = total cost / number of gallons = total cost/105.8

Step-by-step explanation:

<h3>a. </h3>

The round-trip distance is the sum of the distances there and back. It is double the one-way distance.

  round-trip distance = 2 × one-way distance

  round-trip distance = 2 × 1058 miles = 2116 miles

__

<h3>b.</h3>

The gas used will be the distance divided by miles per gallon.

  gas used = round-trip distance / miles-per-gallon

  gas used = (2116 mi)/(20 mi/gal) = 105.8 gal

__

<h3>c.</h3>

The cost of gas will be the product of cost per gallon and number of gallons.

  cost of gas = cost-per-gallon × gallons

  cost of gas = $2.89/gal × 105.8 gal = $305.762 ≈ $305.76

__

<h3>d.</h3>

The relation used in the previous step can be used to find the cost per gallon. Divide that equation by gallons to get ...

  (cost of gas)/gallons = cost-per-gallon

For the same trip, the number of gallons is 105.8, so the equation becomes ...

  cost-per-gallon = (cost of gas)/105.8

3 0
2 years ago
rhombus and a square have one and the same side of 6 cm. The area of the rhombus is 4/5 of the area of the square. Find the heig
siniylev [52]
Consider this option:
1. area_rombus=a*h, where a=6 - the length of the side, h - height.
h=area_rombus/a.
2. area_sq=a², where a=6 - the length of the square.
area_sq=36, area_rombus=4/5 *36=28.8.
3. according to the item 1 h=area_rombus/a=28.8/6=4.8.

answer: 4.8
6 0
3 years ago
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