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Fiesta28 [93]
2 years ago
6

Why is the sum of forces/net force less than the applied force? Think about the direction of the forces in your answer

Physics
1 answer:
Reil [10]2 years ago
3 0

Answer:

he same direction the magnitude of the resultant is equal to the scalar sum of the magnitude of the forces, but if they are applied in different directions the magnitude must be found using the Pythagorean theorem

Explanation:

When there are several applied forces, if they are all in the same direction the magnitude of the resultant is equal to the scalar sum of the magnitude of the forces, but if they are applied in different directions the magnitude must be found using the Pythagorean theorem, so which the resulting dowry is less than the sum of the magnitudes.

Let's carry out an example with two forces, F1 and F2 of equal magnitudes

if they are in the same direction

           F_total = F₁ + F₂ = 2 F

if they are at 90º

          F_total = \sqrt{F_1^2 + F_2^2}= \sqrt{2}  \ F

if they are at 180º

          F_total = F₁ -F₂ = 0

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Answer:

Explanation:

3.75 * 10^-7

=3.75 * 1/10^7

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8 0
3 years ago
A test of the prototype of a new automobile shows that the minimum distance for a controlled stop from 95 km/h to zero is 55 m.
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Answer:

-0.64525g

Explanation:

t = Time taken for the car to stop

u = Initial velocity = 95 km/h

v = Final velocity = 0 km/h

s = Displacement

a = Acceleration

Equation of motion

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-95^2}{2\times 0.055}\\\Rightarrow a=-82045.45\ km/h^2

Converting to m/s²

a=82045.45=\frac{82045.45\times 1000}{3600\times 3600}=-6.33\ m/s^2

g = Acceleration due to gravity = 9.81 m/s²

Dividing both the accelerations, we get

\frac{a}{g}=\frac{-6.33}{9.81}=-0.64525\\\Rightarrow a=-0.64525g

Hence, acceleration of the car is -0.64525g

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