Explanation:
<u>Chromosomes store genetic information. </u>
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All the genetic information within the eukaryotic cell is preserved as helical DNA within the nucleus. This DNA is tightly wrapped around histones as chromosomes.
Further Explanation:
DNA sequences contain genes that may have different forms called alleles. The genotype of DNA is transcribed into mRNA and subsequently translated into amino acids that are linked together by rRNA to form proteins that form the phenotype of an organism. Mutations in the DNA sequences affect the corresponding mRNA and therefore the encoded protein
Spontaneous changes that occur within the genome during the cell division process, called mutations. These errors occur as copies of DNA are produced inside the cell; mutations can range from small modifications, called single nucleotide polymorphisms, to large-scale deletions and multi-gene additions.
Learn more about mutations at brainly.com/question/4602376
Learn more about DNA and RNA at brainly.com/question/2416343?source=aid8411316
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Answer:
Explanation:
If severe, anxiety and fear, can affect a client's condition during and after surgery. During the surgical process, an anxious client will respond poorly to the surgery .The patient may also be prone to other complications.
Extreme anxiety may cause unpleasant symptoms and stress such as a pounding heart, a racing heart (fast pulse), irregular heartbeat, nausea, a nervous stomach, shortness of breath and sleep problems. Also, during the surgical process, anxiety can make pain worse, as well as making it harder to cope with the pain.
In addition, anxiety can also make it harder to understand and remember important advices given to the patient about the operation, such as how to prepare for it or about recovering afterwards.
A sliding friction occurs as a fish swims through water.
Answer:
here's is your answer buddy
Explanation:
The plants in the F1 generation were allowed to self-pollinate. The plants in the P generation are true breeding.
Answer:
We have two alleles, XA and Xa and the genotypic frequencies are given by p^2 + 2pq + q^2 = 1
In this equation XA is p and Xa is q. Therefore p^2 is the frequency of the genotype XAXA, etc.
For X-linked conditions, females have 2 alleles for the gene, but males only have one. So calculate the genotypic frequencies for males and females separately. Since the population is in Hardy-Weinberg equilibruim, the allelic frequency is the same for both sexes.
Since males only have one X chromosome, the frequency of X linked in male is equal to the allelic frequency. So frequency just equals 1/5000 or 0.0002
so q^2 = q for males in X linked
So q = 0.0002
for females, she would need to have both alleles, so her frequency of the homozygous genotype is q^2 = 0.0002^2 = 0.00000004
number of affected females would be q^2 x number of females in the population
so 0.00000004 x 160 mil = 6.4 females would have hemophilia.
Explanation:
