3 years ago

True or False, Water Stores In Snow And Ice Can Return Directly To The Atmosphere Through The Process Of Sublimation

Physics

1 answer:

IgorC [24]3 years ago

4 0

Your answer is positively true

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What is the speed of a 200-kilogram car that is driving with 2000 joules of kinetic energy? (SHOW ALL WORK)

Katyanochek1 [597]

Answer:

v ≈ 4.47

Explanation:

The Formula needed = KE = $\frac{1}{2}$ m v²

Substitute with numbers known:

2000J = $\frac{1}{2}$ × 200kg × v²

Simplify:

÷100 ÷100 (Divide by 100 on both sides)

2000J = 100 × v²

$\frac{2000J}{100}$ = v²

20 = v²

√ √ (Square root on both sides)

√20 = √v²

4.472135955 = v (Round to whatever the question asks)

v ≈ 4.47 (I rounded to 2 decimal places or 3 significant figures, as that is what it usually is)

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4 years ago

What length of a certain metal wire of diameter 0.15 mm is needed for the wire to have a resistance of 15 ω? the resistivity of

Murljashka [212]

The resistance of the cylindrical wire is $R=\frac{\rho l}{A}$ .

Here $R$ is the resistance, $l$ is the length of the wire and $A$ is the area of cross section. Since the wire is cylindrical $A=\frac{\pi d^2}{4}$ . Rearranging the above equation,

$A=\frac{\rho l}{R}\\ \frac{\pi d^2}{4}=\frac{\rho l}{R}\\ l=\frac{\pi d^2 R}{4 \rho}$

Here $d=0.15, R=15, \rho=1.68(10^{-8})$ .

Substituting numerical values,

$l=\frac{\pi 0.15^2(10^{-6}) (15)}{4 (1.68)(10^{-8})} \\ l=15.78$

The length of the wire is $15.78 \;\;m$

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