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-Dominant- [34]
3 years ago
13

Heeeelllllllpppp I need this right now

Physics
2 answers:
dem82 [27]3 years ago
7 0
Static friction

hope this helps
Elenna [48]3 years ago
5 0
Static friction hope this helps you
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Jfdojbfkkjds vdf;ifdfdi
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Answer:

hsjishhdhjs jdjyshskksndhu

6 0
3 years ago
Listed following are three possible models for the long-term expansion (and possible contraction) of the universe in the absence
Keith_Richards [23]

Answer:

1. Recollapsing universe

2. Critical universe

3. Coasting universe

Explanation:

Recollapsing universe has dark matter density greater than critical density. While critical universe has its matter density equal to the critical sensity. Coasting universe on the other hand has much smaller matter density compared to critical density.

Note that the critical density is approximately 10^-20 grams/cm3

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3 years ago
The decibel level of an orchestra is 90 db, and the violin section achieves a level of 80 dB. How does the sound intensity from
skad [1K]

Answer:

The difference in the decibel corresponses to a constant difference in the loudness perceived.

The refore the sound intensity from the orchestra is like 100 times that of the violin.

Explanation:

4 0
3 years ago
In the modern model of the atoms over 99.9% of the atoms is made up of:
QveST [7]
In the modern model of the atoms over 99.9℅ of the atom is made up of empty space
3 0
3 years ago
Read 2 more answers
A car is strapped to a rocket (combined mass = 661 kg), and its kinetic energy is 66,120 J.
aliina [53]

Answer:

9.43 m/s

Explanation:

First of all, we calculate the final kinetic energy of the car.

According to the work-energy theorem, the work done on the car is equal to its change in kinetic energy:

W=K_f - K_i

where

W = -36.733 J is the work done on the car (negative because the car is slowing down, so the work is done in the direction opposite to the motion of the car)

K_f is the final kinetic energy

K_i = 66,120 J is the initial kinetic energy

Solving,

K_f = K_i + W = 66,120 + (-36,733)=29,387 J

Now we can find the final speed of the car by using the formula for kinetic energy

K_f = \frac{1}{2}mv^2

where

m = 661 kg is the mass of the car

v is its final speed

Solving for v, we find

v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(29,387)}{661}}=9.43 m/s

3 0
3 years ago
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