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lbvjy [14]
3 years ago
12

1. बालू के एक कण की त्रिज्या 1.6 x 10-4मी है। इस कण की त्रिज्या

Physics
1 answer:
Over [174]3 years ago
5 0

Answer:

BOIIII english????

Explanation:

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The largest single publication in the world is the 1112-volume set of British Parliamentary Papers for 1968 through 1972. The co
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Answer:

m_l=550\ kg is the mass of librarian.

Explanation:

Given:

  • mass of the system, m_s=3.3\times 10^{3}\ kg
  • velocity of librarian relative to the ground, v_l=2.5\ m.s^{-1}
  • velocity of the cart relative to the ground, v_c=0.5\ m.s^{-1}

N<u>ow using the principle of elastic collision:</u>

Net momentum of the system is zero.

m_l\times v_l=(3300-m_l)\times v_c

m_l\times 2.5=(3300-m_l)\times 0.5

m_l=550\ kg is the mass of librarian.

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Parallax angles of less than 0.01 arcsec are very difficult to measure from Earth because of the effects of the Earth's atmosphere. This limits Earth based telescopes to measuring the distances to stars about 1/0.01 or 100 parsecs away.
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3 years ago
Does 59feet =170000 meters
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Only one of three balls A, B, and C carries a net charge q. The balls are made from conducting material and are identical. One o
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Answer:

This is greater than the initial charge, which violates the principle that the charge cannot be created or destroyed, consequently this distribution is impossible to achieve

Explanation:

The metals distribute the charge on all surface when they touch the surface increases so that charge density decreases and when the charge is separated into smaller in each metal.

Let's apply this principle to our case.

One of the spheres is loaded with a charge q, when touching a ball its charge is reduced to 1 / 2q for each ball.

         qA = ½ q

         qB = ½ q

         qC = 0

The total charge is q

we make a second contact

If we touch the ball A again with the other sphere not charged C, the chare is distributed and when separated it is reduced by half

         qA = 1/2 (q / 2) = ¼ q

         qC = ¼ q

         qB = ½ q

At this point all spheres have a charge,

      qA = ¼ q

      qb = ½ q

      qC = ¼ q

The total charge is q

Now let's contact spheres B and one of the other two

       Q = ½ q + ¼ q = ¾ q

When splitting the charge

        qB = ½ ¾ q = 3/8 q

        qC = ½ ¾ q = 3/8 q

        qA = ¼ q

The total charge is q

Note that the total load is always equal to q

Now let's analyze the given configuration

Let's look for the total load

       Q = qA + QB + QC

       Q = ½ q + 3/8 q + ¼ q

        Q = 9/8 q

This is greater than the initial charge, which violates the principle that the charge cannot be created or destroyed, consequently this distribution is impossible to achieve

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Oxygen, hydrogen, sodium, chlorine, lead, iron. Hope this helps!!!


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