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stich3 [128]
3 years ago
14

What kind of image does the lens in a camera produce? real and upside down real and right-side up virtual and upside down virtua

l and right-side up
Physics
2 answers:
Vlada [557]3 years ago
7 0

Answer:

<u>real and upside down </u>

Explanation:

Lens of a camera gathers light and focuses it on the light detector or film strip. <u>A real and inverted (upside -down) image is formed. </u>This image is then stored and processed and inverted. Thereafter we see an upright image. A chemical reaction on the film strip stores the image. In a digital lens, a light detector such as CCD stores the image.

damaskus [11]3 years ago
6 0

Answer:

real and upside down

Explanation:

As we know that images taken by the camera is stored on the film inside the camera.

Here in this phenomenon the lens inside the camera is used to take the images of objects and that images are formed on the film.

Since we know that only real images can be formed on the screen which are also inverted images so here we can say that for all given cases of camera the images must be real and it is upside down.

So here correct answer will be

real and upside down

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3 years ago
Use the worked example above to help you solve this problem. An Alaskan rescue plane drops a package of emergency rations to str
Vlad [161]

Answer:

(a) The package lands 682 meters horizontally ahead from the point the package was dropped from the plane

(b) The horizontal component = 39.0 m/s

The vertical component = 171.55 m/s

(c) The angle of impact is 77.19°

Explanation:

The parameters given are;

Velocity of the plane, vₓ = 39.0 m/s

Height of the plane above the ground, h = 1.50 × 10² m = 1,500 m

(a) The time, t, before the package hits the ground when dropped from the plane is given by the relation;

h = u·t + 1/2×g×t²

Where:

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u = Initial vertical velocity = 0 m/s

Hence;

1500 = 0×t + 1/2 × 9.81 × t² = 4.905·t²

∴ t = √(1500/4.905) = 17.49 s

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The package lands 682 meters horizontally ahead from the point the package was dropped from the plane

(b) The vertical velocity, v_y, of the package just before landing is given by the relation;

v_y² = u² + 2·g·h

u = 0 m/s

∴ v_y² = 0 + 2×9.81×1500 = 29430 m²/s²

v_y = √29430  = 171.55 m/s

Hence the horizontal component = 39.0 m/s

The vertical component = 171.55 m/s

(c) The angle of impact, θ, is given as follows;

tan \theta = \dfrac{v_y}{v_x}  = \dfrac{171.55}{39.0 } = 4.4

∴ θ = tan⁻¹(4.4) = 77.19°.

6 0
4 years ago
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alexgriva [62]

Answer:

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Explanation:

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           V_{p} is the voltage in the primary coil

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From the given question,

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5 0
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3 years ago
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