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stich3 [128]
3 years ago
14

What kind of image does the lens in a camera produce? real and upside down real and right-side up virtual and upside down virtua

l and right-side up
Physics
2 answers:
Vlada [557]3 years ago
7 0

Answer:

<u>real and upside down </u>

Explanation:

Lens of a camera gathers light and focuses it on the light detector or film strip. <u>A real and inverted (upside -down) image is formed. </u>This image is then stored and processed and inverted. Thereafter we see an upright image. A chemical reaction on the film strip stores the image. In a digital lens, a light detector such as CCD stores the image.

damaskus [11]3 years ago
6 0

Answer:

real and upside down

Explanation:

As we know that images taken by the camera is stored on the film inside the camera.

Here in this phenomenon the lens inside the camera is used to take the images of objects and that images are formed on the film.

Since we know that only real images can be formed on the screen which are also inverted images so here we can say that for all given cases of camera the images must be real and it is upside down.

So here correct answer will be

real and upside down

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A child in a boat throws a 5.80-kg package out horizontally with a speed of 10.0 m/s. The mass of the child is 24.6kg and the ma
Sergio [31]

Answer:

-0.912 m/s

Explanation:

When the package is thrown out, momentum is conserved. The total momentum after is the same as the total momentum before, which is 0, since the boat was initially at rest.

(m_c + m_b)v_b + m_pv_p = 0

where m_c = 24.6 kg, m_b = 39 kg, m_p = 5.8 kg are the mass of the child, the boat and the package, respectively. , v_p = 10m/s, v_b are the velocity of the package and the boat after throwing.

(24.6 + 39)v_b + 5.8*10 = 0

63.6v_b + 58 = 0

v_b = -58/63.6 = -0.912 m/s

3 0
3 years ago
Now in "real life," this automobile is cruising at 20.5 m/s (equal to 73.8 km/hr) when it is about to hit a pedestrian stuck in
algol13

Answer:

He needs 1.53 seconds to stop the car.

Explanation:

Let the mass of the car is 1500 kg

Speed of the car, v = 20.5 m/s

He will not push the car with a force greater than, F=2\times 10^4\ N

The impulse delivered to the object is given by the change in momentum as :

F\times t=mv\\\\t=\dfrac{mv}{F}\\\\t=\dfrac{1500\times 20.5}{2\times 10^4}\\\\t=1.53\ s

So, he needs 1.53 seconds to stop the car. Hence, this is the required solution.

5 0
3 years ago
A certain mass of a gas occupies 2 litres at 27 °C and 100
Zielflug [23.3K]

Answer:

75k

Explanation:

You can see solution in the picture

3 0
2 years ago
Three equal 1.55-μC point charges are placed at the corners of an equilateral triangle whose sides are 0.500 m long. What is the
kati45 [8]

Answer:

0.12959085 J

Explanation:

k = Coulomb constant = 8.99\times 10^{9}\ Nm^2/C^2

q = Charge = 1.55 μC

d = Distance between charge = 0.5 m

Electric potential energy is given by

U=k\dfrac{q^2}{d}

In this system with three charges which are equidistant from each other

U=k\dfrac{q^2}{d}+k\dfrac{q^2}{d}+k\dfrac{q^2}{d}

\\\Rightarrow U=k\dfrac{3q^2}{d}\\\Rightarrow U=8.99\times 10^9\times \dfrac{3\times (1.55\times 10^{-6})^2}{0.5}\\\Rightarrow U=0.12959085\ J

The potential energy of the system is 0.12959085 J

6 0
3 years ago
A graph that plots the temperature of a star against its brightness.
Ostrovityanka [42]

Answer:

C. HertzPrung Russel Diagram

Explanation:

The Hertzsprung–Russell diagram, or H–R diagram, is a plot of stellar luminosity against surface temperature. Most stars lie on the main sequence, which extends diagonally across the H–R diagram from high temperature and high luminosity to low temperature and low luminosity.

5 0
3 years ago
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