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stich3 [128]
3 years ago
14

What kind of image does the lens in a camera produce? real and upside down real and right-side up virtual and upside down virtua

l and right-side up
Physics
2 answers:
Vlada [557]3 years ago
7 0

Answer:

<u>real and upside down </u>

Explanation:

Lens of a camera gathers light and focuses it on the light detector or film strip. <u>A real and inverted (upside -down) image is formed. </u>This image is then stored and processed and inverted. Thereafter we see an upright image. A chemical reaction on the film strip stores the image. In a digital lens, a light detector such as CCD stores the image.

damaskus [11]3 years ago
6 0

Answer:

real and upside down

Explanation:

As we know that images taken by the camera is stored on the film inside the camera.

Here in this phenomenon the lens inside the camera is used to take the images of objects and that images are formed on the film.

Since we know that only real images can be formed on the screen which are also inverted images so here we can say that for all given cases of camera the images must be real and it is upside down.

So here correct answer will be

real and upside down

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pishuonlain [190]

The package should be dropped <u>678 m</u> short of the target.

A package dropped from a plane which is moving at a speed v, has a horizontal velocity equal to the horizontal velocity of the plane. It has a parabolic trajectory, traversing a horizontal range x while it falls through a vertical height y.

The package has no initial vertical velocity, and it falls through a height y under the action of the acceleration due to gravity g.

Use the equation,

y=\frac{1}{2} gt^2

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t^2=\frac{2y}{g}

Substitute 100 m for y and 9.81m/s² for g.

t^2=\frac{2y}{g}\\ =\frac{2(100m)}{9.81m/s^2} \\ =20.39s^2\\ t=4.52s

In the time t  the package travels a horizontal distance x. The horizontal velocity of the package remains constant, since no force acts along the horizontal direction.

Therefore, the horizontal distance traveled by the package is given by,

x=vt\\ =(150m/s)(4.52s)\\ =678m

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6 0
4 years ago
A ray diagram without the produced image is shown.
4vir4ik [10]

A car acting as an object in front of a biconvex lens between F and 2 F on the object side of the lens. There is a light ray parallel to the principal axis that is bent through F on the image side of the lens. There is a ray straight through the center of the lens. The rays intersect below the x axis further than 2 F away from the lens and farther from the principal axis than the object is tall.

<u> The image produced by the lens is (b) inverted and real</u>

Explanation:

A real image occurs where the rays converge.

Real images can be produced both by the  concave mirrors or  converging lenses, but the condition is that the object of consideration is always  placed far  away from the mirror or the lens than the focal point, and thus the  real image produced is inverted.

A car acting as an object in front of a biconvex lens between F and 2 F on the object side of the lens. There is a light ray parallel to the principal axis that is bent through F on the image side of the lens. There is a ray straight through the center of the lens. The rays intersect below the x axis further than 2 F away from the lens and farther from the principal axis than the object is tall.

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3 years ago
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torisob [31]

Answer is C: Ability to see three-dimensional images of the surfaces of object

Explanation:

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8 0
3 years ago
With the aid of a suitable diagram, explain what is meant by an electromagnetic wave.
suter [353]

Answer:

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3 0
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notka56 [123]
Incomplete question.  Full text is:

"<span>Give an example of a situation in which you would describe an object's position in (a) one-dimension coordinates (b) two-dimension coordinates (c) three-dimension coordinates"

Solution
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(c) The position of an airplane in the air: in this case we need 3 coordinates, the height, the latitude and the longitude of the airplane.</span>
8 0
3 years ago
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