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3 years ago

Compressing a spring increases its

Chemistry

1 answer:

VashaNatasha [74]3 years ago

3 0

Answer:

B. potential energy

Explanation:

Potential energy ( Mechanical in this case ) is energy stored by force. so If you are compressing a spring you are increasing more potential to it by force.

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A (what) forms when the sperm first fertilizes an egg

Arlecino [84]

Fertilization occurs when the nucleus of both a sperm and egg fuse to form a diploid cell known as zygote the successful fusion of gametes forms a new organization

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3 years ago

How do electrons in a metallic bond behave?

igomit [66]

Hello,

In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “sea” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions.

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3 years ago

H3PO4 +CaCOH)2=Ca3(PO4)2+H20<br> The equation balance

AnnyKZ [126]

Answer:

2H3PO4 +3Ca(OH) 2 = Ca3 (PO4) 2 +6H20

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3 years ago

A student dissolves 15.0 g of ammonium chloride(NH4Cl) in 250. 0 g of water in a well-insulated open cup. She then observes the

iren2701 [21]

Answer:

1) Endothermic.

2) $Q_{rxn}=4435.04J$

3) $\Delta _rH=15.8kJ/mol$

Explanation:

Hello there!

1) In this case, for these calorimetry problems, we can realize that since the temperature decreases the reaction is endothermic because it is absorbing heat from the solution, that is why the temperature goes from 22.00 °C to 16.0°C.

2) Now, for the total heat released by the reaction, we first need to assume that all of it is released by the solution since it is possible to assume that the calorimeter is perfectly isolated. In such a way, it is also valid to assume that the specific heat of the solution is 4.184 J/(g°C) as it is mostly water, therefore, the heat released by the reaction is:

$Q_{rxn}=-(15.0g+250.0g)*4.184\frac{J}{g\°C}(16.0-20.0)\°C\\\\ Q_{rxn}=4435.04J$

3) Finally, since the enthalpy of reaction is calculated by dividing the heat released by the reaction over the moles of the solute, in this case NH4Cl, we proceed as follows:

$\Delta _rH=\frac{ Q_{rxn}}{n}\\\\\Delta _rH= \frac{ 4435.04J}{15.0g*\frac{1mol}{53.49g} } *\frac{1kJ}{1000J} \\\\\Delta _rH=15.8kJ/mol$

Best regards!

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2 years ago

For the vaporization reaction Br2(l) → Br2(

oksian1 [2.3K]

The temperature at which the process be spontaneous is calculated as follows

delta G = delta H -T delta S

let delta G be =0

therefore delta H- T delta s =0

therefore T= delta H/ delta S
convert 31 Kj to J = 31 x1000= 31000 j/mol

T=31000j/mol /93 j/mol.k =333.33K

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3 years ago