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taurus [48]
3 years ago
12

Hypothesis II: Write the equation with Iron (III) Chloride and balance it: Iron + Copper (II) chloride --> Iron (III) chlorid

e + Copper
Chemistry
1 answer:
stich3 [128]3 years ago
5 0

Answer:

Fe + CuCl2 = FeCl2 + Cu

Explanation:

This is already balanced.

You might be interested in
Consider the following reversible reaction.
dmitriy555 [2]

Answer:

Keq = [CO₂]/[O₂]

Explanation:

Step 1: Write the balanced equation for the reaction at equilibrium

C(s) + O₂(g) ⇄ CO₂(g)

Step 2: Write the expression for the equilibrium constant (Keq)

The equilibrium constant is equal to the product of the concentrations of the products raised to their stoichiometric coefficients divided by the product of the concentrations of the reactants raised to their stoichiometric coefficients. It only includes gases and aqueous species. The equilibrium constant for the given system is:

Keq = [CO₂]/[O₂]

6 0
3 years ago
Read 2 more answers
The number of periods/series in Mendeleev's Periodic table is<br>A. 10<br>B. 13<br>C. 12<br>D. 14​
butalik [34]

Answer: The number of series in Mendeleev's Periodic table is 12.

Explanation:

Horizontal rows present in the periodic table are called periods. Vertical rows in the periodic table are called series.

Mendeleev gave periodic table in the year 1869 by arranging elements according to their atomic weights a in tabular form.  

Mendeleev's periodic table depicts 12 periods/series.

Thus, we can conclude that the number of periods/series in Mendeleev's Periodic table is 12.

5 0
3 years ago
Write the balanced chemical reaction for the following nitrogen cycle reactions. These reactions are mediated by bacteria and pl
Leto [7]

Answer:

Nitrification is a biological process by which ammonia is oxidized to nitrites (NO_{2} ^{-}) and then to nitrates (NO_{3} ^{-}) by action of specialized bacteria in nature (such as <em>nitrosomonas</em> and <em>nitrobacter</em>).

Explanation:

This two-step process utilizes molecular atmospheric oxygen and ammonia and ammonium components of soil and nature.

<em>(a.) Ammonia and ammonium compounds to nitrite</em>

NH_{4} ^{+} + O_{2} → NO_{2} ^{-} + 4H^{+}

2NH_{3} ^{+} + 3O_{2} → 2NO_{2} ^{-} + 2H^{+} + 2H_{2} O

<em>(b.) Nitrite to nitrate</em>

2NO_{2} ^{-} + O_{2} → 2NO_{3} ^{-} + energy

<em>(c.) The reverse process involves reduction of nitrates to molecular nitrogen, called denitrification (with succinic acid in the equation below).</em>

4NO_{3} ^{-} + 10H^{+} + (CH_{2})_{2}(COOH)_{2} → 2N_{2} +4CO_{2}  + 8 H_{2} O

(NO and N_{2}O is an intermediate product in this process.)

4 0
3 years ago
The sulfate ion is an example of a(n) __________ because it contains two different elements.
myrzilka [38]

it is an example of a compound

5 0
3 years ago
2. The last electron in arsenic occupies a 4p level. What block
Romashka-Z-Leto [24]

Answer:

Arsenic is present in p block and group fifteen of periodic table.

Explanation:

The atomic number of Arsenic is 33.

According to the Aufbau principal in ground state of elements electron first occupy the lower energy level then fill the higher energy levels. We know that there four subshells s, p, d and f. The maximum number of electrons in these subshells can be calculated by following formula:

2 (2l +1 )

and l = 0,1,2,3,....

maximum numbers of electrons in s subshell are,

l=0

2 ( 2(0) + 1)

2

so maximum electrons in s subshell are 2.

maximum numbers of electrons in p subshell are,

l = 1

2 ( 2(1) + 1)

2( 2 + 1)

6

so maximum electrons in p subshell are 6.

maximum numbers of electrons in d subshell are,

l = 2

2 ( 2(2) + 1)

2( 4 + 1)

10

so maximum electrons in d subshell are 10.

maximum numbers of electrons in f subshell are,

l = 3

2 ( 2(3) + 1)

2( 6 + 1)

14

so maximum electrons in f subshell are 14.

Electron first fill 1s subshell then 2s subshell and in this way they goes to higher energy levels.

Electronic configuration of Arsenic:

1s2 2s2 2p6 3s2 3p6 4s2 3d10, 4p3

The last electron is present in p subshell that's way Arsenic is present in p block of periodic table.

P block elements are non-metals, metals and metalloids. These are thirty five elements. The P-block elements are present on right side of periodic table. There valance electrons are present in P orbital. The p-block metals are shiny and good conductor of heat and electricity. These metal lose the electron which is accept by non metals and form ionic bond. They have high melting points.

Metalloids includes boron, silicon, germanium, arsenic, antimony and tellurium. Metalloids contain both the properties of metals and non metals, Some metalloids are toxic like arsenic.

Most of p-block elements are non metals. They are bad conductor of heat and electricity and have low boiling points.

6 0
3 years ago
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