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3 years ago

DUE IN 10 MINUTES I WILL MAKE YOU BRAINILIST

Chemistry

1 answer:

neonofarm [45]3 years ago

4 0

Answer:

Ernest Rutherford postulated the nuclear structure of the atom, discovered alpha and beta rays, and proposed the laws of radioactive decay. He received the Nobel Prize in Chemistry in 1908.

Erwin Schrödinger proposed the quantum mechanical model of the atom, which treats electrons as matter waves. ... The Heisenberg uncertainty principle states that we can't know both the energy and position of an electron.

hope it helps

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how does the kinetic energy of a substance's particle in the solid phase compare to their kinetic enegy in the liquid phase?

iVinArrow [24]

The kinetic energy in the solid and liquid phases is the same. The kinetic energy of the substance's particles will depend on the volume of the substance. The particles have less kinetic energy in the liquid phase than they do in the gas phase. ... They vibrate so quickly that the particles ionize and become plasma.

vote brainliest if this helped! :)

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4 years ago

Structure of 4-isopropyl-2,4,5-triethylheptane

SIZIF [17.4K]

Answer:

See the attached file

Explanation:

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3 years ago

Most important factor in determining an element's place in the periodic table

Monica [59]

The number of Protons.
(which is also the ATOMIC NUMBER)

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3 years ago

Vanadium (V) and oxygen (O) form a series of compounds with the following compositions: Mass % V 76.10 67.98 61.42 56.02 Mass %

11Alexandr11 [23.1K]

Answer:

For every given mass of Vanadium, the relative number of oxygen atoms present or the mole ratio of Oxygen to Vanadium is:

A. 1:1

B. 3:2

C. 2:1

D. 5:2

Note: The question is stated more clearly below:

Vanadium (V) and oxygen (O) form a series of compounds with the following compositions: Mass % V 76.10 67.98 61.42 56.02 Mass % O 23.90 32.02 38.58 43.98 Compound Mass % N 1 33.28 2 39.94.

What are the relative numbers of atoms of oxygen in the compounds for a given mass of vanadium?

Explanation:

Number of moles in 100 g mass = % mass / molar mass

Molar mass of Vanadium, V = 51 g/mol

Molar mass of oxygen atom, O = 16 g/mol

1. Percentage mass of V and O is 76.10% and 23.90% respectively.

Number of moles of each atom;

V = 76.10/51.0 = 1.5 moles

O = 23.9/16 = 1.5 moles

Mole ratio of oxygen to vanadium = 1.5/1.5 = 1 : 1

2. Percentage mass of V and O is 67.98% and 32.02% respectively

Number of moles of each atom:

V = 67.98/51 = 1.33

O = 32.02/16 = 2

Mole ratio of oxygen to vanadium = 2/1.33 = 1.5 : 1 = 3 : 2

3. Percentage mass of V and O is 61.42% and 38.58% respectively

Number of moles of each atom:

V = 61.42/51 = 1.2

O = 38.58/16 = 2.4

Mole ratio of oxygen to vanadium = 2.4/1.2 = 2 : 1

4. Percentage mass of V and O is 56.02% and 43.98% respectively

Number of moles of each atom:

V = 56.02/51 = 1.10

O = 43.98/16 = 2.75

Mole ratio of oxygen to vanadium = 2.75/1.10 = 2.5 : 1 = 5 : 2

6 0

3 years ago

Find the mass, in grams, of 5.00*10^23 molecules of F2

Westkost [7]

Answer: 31.55 g

Explanation:

- The mass number of Fluoride atom (F) = 18.99 g/mol, so mass number of fluorine gas (F2) = 37.98 g/mol.

- 1 mole of (F2) [which has 37.98 g/mol] contains Avogadro’s number of molecules (6.02×10^23 molecules),

so 1 mole of (F2) with 37.98 g/mol → 6.02×10^23 molecules.

- Using cross multiplication,

37.98 g/mol of (F2) → 6.02 ×10^23 molecules

? → 5.00 ×10^23 molecules

Hence the mass of 5.00×10^23 molecules of F2 = (37.98 × 5.00 × 10^23) / 6.02 ×10^23 = 31.55 g..

7 0

4 years ago