How many joules are absorbed when 64.3 grams of water is heated from 40.0 °C to 74.0 °C?
2 answers:
Answer : The correct option is, (B) 9150 joules
Explanation : Given,
Initial temperature =
Final temperature =
Mass of water = 64.3 g
Specific heat of water =
Formula used :
or,
where,
Q = heat absorbed = ?
m = mass of water
= specific heat of water
= initial temperature
= final temperature
Now put all the given value in the above formula, we get:
Therefore, the heat absorbed will be, 9150 J
You might be interested in
Answer:
The correct answer is option D.
Explanation:
Rate of the reaction is a change in the concentration of any one of the reactant or product per unit time.
Rate of the reaction:
Rate of decrease in nitrogen dioxide concentration is equal to the rate of decrease in carbon monoxide.
Given rate expression of the reaction:
Rate of the reaction on doubling concentration of nitrogen dioxide and carbon monoxide : R'
Doubling the concentrations of nitrogen dioxide and carbon monoxide simultaneously will increase the rate of the reaction by a factor of eight.
Hence, none of the given statements are true.