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maw [93]
3 years ago
15

How many joules are absorbed when 64.3 grams of water is heated from 40.0 °C to 74.0 °C?

Chemistry
2 answers:
REY [17]3 years ago
6 0

Answer : The correct option is, (B) 9150 joules

Explanation : Given,

Initial temperature = 40.0^oC

Final temperature = 74.0^oC

Mass of water = 64.3 g

Specific heat of water = 4.184J/g^oC

Formula used :

Q=m\times C_w\times \Delta T

or,

Q=m\times C_w\times (T_2-T_1)

where,

Q = heat absorbed = ?

m = mass of water

C_w = specific heat of water

T_1 = initial temperature

T_2 = final temperature

Now put all the given value in the above formula, we get:

Q=64.3g\times 4.184J/g^oC\times (74-40)^oC

Q=9150J

Therefore, the heat absorbed will be, 9150 J

Alinara [238K]3 years ago
3 0
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How much heat energy is needed to heat 300g of water from 10 degrees Celsius to 50 degrees Celsius
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Answer:

There is 50.2 kJ heat need to heat 300 gram of water from 10° to 50°C

Explanation:

<u>Step 1: </u>Data given

mass of water = 300 grams

initial temperature = 10°C

final temperature = 50°C

Temperature rise = 50 °C - 10 °C = 40 °C

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<u>Step 2:</u> Calculate the heat

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2 years ago
During an investigation, a student burns magnesium to form magnesium oxide. The starting mass of magnesium is measured as 21.3 g
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Answer:

Percentage yield = 85.2%

Explanation:

Given data:

Mass of Mg = 21.3 g

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Percentage yield = ?

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Number of moles of Mg = mass/molar mass

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Now we will compare the moles of MgO with Mg.

                 Mg           :               MgO

                 2               :               2

                0.88             :             0.88

Mass of MgO:           

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