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maw [93]
3 years ago
15

How many joules are absorbed when 64.3 grams of water is heated from 40.0 °C to 74.0 °C?

Chemistry
2 answers:
REY [17]3 years ago
6 0

Answer : The correct option is, (B) 9150 joules

Explanation : Given,

Initial temperature = 40.0^oC

Final temperature = 74.0^oC

Mass of water = 64.3 g

Specific heat of water = 4.184J/g^oC

Formula used :

Q=m\times C_w\times \Delta T

or,

Q=m\times C_w\times (T_2-T_1)

where,

Q = heat absorbed = ?

m = mass of water

C_w = specific heat of water

T_1 = initial temperature

T_2 = final temperature

Now put all the given value in the above formula, we get:

Q=64.3g\times 4.184J/g^oC\times (74-40)^oC

Q=9150J

Therefore, the heat absorbed will be, 9150 J

Alinara [238K]3 years ago
3 0
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